Php Json数组到数组
我有一个来自laravel的JSON数组,如下所示:Php Json数组到数组,php,arrays,json,mongodb,php-mongodb,Php,Arrays,Json,Mongodb,Php Mongodb,我有一个来自laravel的JSON数组,如下所示: Illuminate\Support\Collection Object ( [items:protected] => Array ( [0] => Array ( [_id] => MongoDB\BSON\ObjectID Object (
Illuminate\Support\Collection Object
(
[items:protected] => Array
(
[0] => Array
(
[_id] => MongoDB\BSON\ObjectID Object
(
[oid] => 5a15e52b5bd98b7a0040fac8
)
[UnitPrice] => 18
[UnitsInStock] => 39
)
[1] => Array
(
[_id] => MongoDB\BSON\ObjectID Object
(
[oid] => 5a15e52b5bd98b7a0040fac9
)
[UnitPrice] => 19
[UnitsInStock] => 17
)
[2] => Array
(
[_id] => MongoDB\BSON\ObjectID Object
(
[oid] => 5a15e52b5bd98b7a0040faca
)
[UnitPrice] => 10
[UnitsInStock] => 13
)
)
)
...
->dataset('UnitPrice', [5,20,100,...]) // array's values = [5,20,100,...]
->dataset('UnitsInStock', [52,120,100,...]) // array's values = [52,120,100,...]
如何仅将UnitPrice
和UnitsInStock
作为一个数组?有没有不使用循环的方法
我想这样使用它:
Illuminate\Support\Collection Object
(
[items:protected] => Array
(
[0] => Array
(
[_id] => MongoDB\BSON\ObjectID Object
(
[oid] => 5a15e52b5bd98b7a0040fac8
)
[UnitPrice] => 18
[UnitsInStock] => 39
)
[1] => Array
(
[_id] => MongoDB\BSON\ObjectID Object
(
[oid] => 5a15e52b5bd98b7a0040fac9
)
[UnitPrice] => 19
[UnitsInStock] => 17
)
[2] => Array
(
[_id] => MongoDB\BSON\ObjectID Object
(
[oid] => 5a15e52b5bd98b7a0040faca
)
[UnitPrice] => 10
[UnitsInStock] => 13
)
)
)
...
->dataset('UnitPrice', [5,20,100,...]) // array's values = [5,20,100,...]
->dataset('UnitsInStock', [52,120,100,...]) // array's values = [52,120,100,...]
Laravel有一个方法来获取给定列的数组。否则,您可以使用PHP的方法
$unitPrices = array_column($items, 'UnitPrice');