Php 具有join 4表的Codeigniter活动记录

伙计们，我有4个表

uhd\u凭证菜单

，

uhd\u菜单

，

uhd\u凭证变体菜单

，

uhd\u变体菜单

哪个

uhd\u凭证菜单

和

uhd\u菜单

通过

菜单id

连接，哪个

uhd\u凭证变型菜单

和

uhd\u凭证菜单

通过

凭证菜单id

连接，最后一个，

uhd\u variant\u菜单

和

凭证\u variant\u菜单

通过

variant\u菜单id

这是我如何获取数据的代码：

        $this->db->select("uhd_voucher_menu.voucher_id,uhd_menu.menu_name,uhd_voucher_menu.qty,uhd_variant_menu.variant_name,uhd_voucher_menu.voucher_menu_id");
        $this->db->from("uhd_voucher_menu");
        $this->db->join("uhd_menu","uhd_menu.menu_id = uhd_voucher_menu.menu_id");
        $this->db->join("uhd_voucher_variant_menu","uhd_voucher_variant_menu.voucher_menu_id = uhd_voucher_menu.voucher_menu_id","left");
        $this->db->join("uhd_variant_menu","uhd_variant_menu.variant_menu_id = uhd_voucher_variant_menu.variant_menu_id","left");
        $this->db->where("voucher_id",$data["voucher"]["voucher_id"]);
        $this->db->where("uhd_menu.restaurant_id",$restaurant_id);
        $res = $this->db->get()->result_array();

从该活动记录将返回到此数据：

[0]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(5) "Spicy"
  ["voucher_menu_id"]=>
  string(1) "3"
}
[1]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(6) "Medium"
  ["voucher_menu_id"]=>
  string(1) "3"
}
[2]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "1"
  ["variant_name"]=>
  string(4) "Sour"
  ["voucher_menu_id"]=>
  string(1) "4"
}
[3]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "1"
  ["variant_name"]=>
  string(6) "Medium"
  ["voucher_menu_id"]=>
  string(1) "4"
}
[4]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(14) "Red Crown Crab"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  NULL
  ["voucher_menu_id"]=>
  string(1) "1"
}
[5]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(8) "Omellete"
  ["qty"]=>
  string(1) "3"
  ["variant_name"]=>
  NULL
  ["voucher_menu_id"]=>
  string(1) "2"
}

[0]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(5) "Spicy"
  ["voucher_menu_id"]=>
  string(1) "3"
}
[1]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(6) "Medium"
  ["voucher_menu_id"]=>
  string(1) "3"
}

正如您所看到的，带有相同的

凭证菜单\u id

的

黄金鲑鱼将返回两次

如果
凭证\u菜单\u id
相同，我想从该数据：

[0]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(5) "Spicy"
  ["voucher_menu_id"]=>
  string(1) "3"
}
[1]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(6) "Medium"
  ["voucher_menu_id"]=>
  string(1) "3"
}
[2]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "1"
  ["variant_name"]=>
  string(4) "Sour"
  ["voucher_menu_id"]=>
  string(1) "4"
}
[3]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "1"
  ["variant_name"]=>
  string(6) "Medium"
  ["voucher_menu_id"]=>
  string(1) "4"
}
[4]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(14) "Red Crown Crab"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  NULL
  ["voucher_menu_id"]=>
  string(1) "1"
}
[5]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(8) "Omellete"
  ["qty"]=>
  string(1) "3"
  ["variant_name"]=>
  NULL
  ["voucher_menu_id"]=>
  string(1) "2"
}

[0]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(5) "Spicy"
  ["voucher_menu_id"]=>
  string(1) "3"
}
[1]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  string(6) "Medium"
  ["voucher_menu_id"]=>
  string(1) "3"
}

我希望数据返回变成这样：

[0]=>
array(5) {
  ["voucher_id"]=>
  string(1) "1"
  ["menu_name"]=>
  string(13) "Golden Salmon"
  ["qty"]=>
  string(1) "2"
  ["variant_name"]=>
  array(2){
    [1]=>
    string(5) "Spicy"
    [2]=>
    string(6) "Medium"
  }
  ["voucher_menu_id"]=>
  string(1) "3"
}

与另一条
金鲑鱼相同
，具有相同的
凭证菜单\u id
4

我希望
变量\u名称
成为数组，以便具有相同
凭证\u菜单\u id
的if数据不会调用两次

伙计们，你们能帮我怎么执行我想要的数据吗？
谢谢（：
您必须使用分组方式，我稍微修改了您的查询：

 $this->db->select("uhd_voucher_menu.voucher_id,uhd_menu.menu_name,uhd_voucher_menu.qty,GROUP_CONCAT(uhd_variant_menu.variant_name SEPARATOR ',') AS variants,uhd_voucher_menu.voucher_menu_id");
    $this->db->from("uhd_voucher_menu");
    $this->db->join("uhd_menu","uhd_menu.menu_id = uhd_voucher_menu.menu_id");
    $this->db->join("uhd_voucher_variant_menu","uhd_voucher_variant_menu.voucher_menu_id = uhd_voucher_menu.voucher_menu_id","left");
    $this->db->join("uhd_variant_menu","uhd_variant_menu.variant_menu_id = uhd_voucher_variant_menu.variant_menu_id","left");
    $this->db->where("voucher_id",$data["voucher"]["voucher_id"]);
    $this->db->where("uhd_menu.restaurant_id",$restaurant_id);
$this->db->group_by("uhd_voucher_menu.voucher_id");
    $res = $this->db->get()->result_array();

查询输出后，我们可以将逗号分隔的值转换为数组

尝试并发布结果…
它只返回1个数据使用echo$this->db->last_query（）发布生成的查询；