Php mysql#u result（$result$i，'；id'；）等效于mysqli

我想将我的代码从

mysql

转换为

mysqli

。 但是，我这里有个问题

mysql

代码是

 for ($i = $start; $i < $end; $i++) {
                    // make sure that PHP doesn't try to show results that don't exist
                    if ($i == $total_results) {
                        break;
                    }





                    // echo out the contents of each row into a table

                      $bookid = mysql_result($result, $i, 'id');
                    $cover = mysql_result($result, $i, 'cover');

                    echo "
                        <div></div>
                <li>
                    <div id='divborder'>
                        <div id='header'>
                            <a class='caption'  href='page.php?id=$bookid '><img src='$cover' alt='' class='headerBg' /></a>
                        </div>
                    </div>
        </li> ";

                }       
echo "</ul></div>";

for（$i=$start；$i<$end；$i++）{
//确保PHP不会试图显示不存在的结果
如果（$i==$total\u结果）{
打破
}
//将每行的内容回显到表中
$bookid=mysql_result（$result，$i，'id'）；
$cover=mysql_result（$result，$i，'cover'）；
回声“

”；
}       
回声“”；

我想把它转换成那样的东西

for ($i = $start; $i < $end; $i++) {
    // make sure that PHP doesn't try to show results that don't exist
    if ($i == $total_results) {
        break;
    }
    $i;
                              $book_row = mysqli_fetch_assoc($result);
                              $book_id = $book_row["id"];
                              $book_cover = $book_row["cover"];
                              $book_title = $book_row["title"];
                              $book_auther1 = $book_row["auther1"];                                  
                              $book_auther2 = $book_row["auther2"];




                    echo "
                        <div></div>
                <li>
                    <div id='divborder'>
                        <div id='header'>
                            <a class='caption caption1'data-title='$data_title'  href='book/$book_id'><img src='$book_cover' alt='' class='headerBg' /></a>
                        </div>
                    </div>
        </li> ";

                }       
echo "</ul></div>";

for（$i=$start；$i<$end；$i++）{
//确保PHP不会试图显示不存在的结果
如果（$i==$total\u结果）{
打破
}
$i；
$book\u row=mysqli\u fetch\u assoc（$result）；
$book_id=$book_行[“id”]；
$book_cover=$book_row[“cover”]；
$book_title=$book_行[“title”]；
$book_auther1=$book_行[“auther1”]；
$book_auther2=$book_行[“auther2”]；
回声“

”；
}       
回声“”；

---

但是

mysql

代码中变量

$i

中的问题我不知道我将把它放在

mysqli

的哪个位置，或者类似这样的东西（来自您的原始代码）：

$query = "select * from books";

// run the query
$result = mysqli_query($query);

// fetch all the rows
$arrayofrows = mysqli_fetch_all($result, MYSQLI_ASSOC);

// then you can use $i from your for loop
// var_dump($arrayofrows[$i]);

---

谢谢你的回答，但我希望代码是过程式的，$i变量，而不是我用于分页的id，我将是计数器，计数一result@AhmedAbuelmagd：已更新答案以处理分页。感谢您的回答，但我希望代码采用过程样式和$i变量，而不是我使用它的id分页一些结果，我将计数器计数一个结果可能你正在寻找这样的东西：我更新了我的答案基于上述链接。
<?php
$conn = mysqli_connect('host','username','password','database');
for ($i = $start; $i < $end; $i++) {
        // make sure that PHP doesn't try to show results that don't exist
        if ($i == $total_results) {
        break;
        }


        $query = "select * from tablename where id ='$i'";
        $result = $conn->query($query);
        $data = mysqli_fetch_all($result,MYSQLI_ASSOC);
        $book_id = $data["id"];
        $book_cover = $data["cover"];
        $book_title = $data["title"];
        $book_auther1 = $data["auther1"];                                  
        $book_auther2 = $data["auther2"];   

        echo "
        <div></div>
        <li>
        <div id='divborder'>
        <div id='header'>
        <a class='caption caption1'data-title='$data_title'  href='book/$book_id'><img src='$book_cover' alt='' class='headerBg' /></a>
        </div>
        </div>
        </li> ";
}   
?>

<?php
$con = mysqli_connect('host','username','password','database');
$per_page=5;

if (isset($_GET['page'])) {
$page = $_GET['page'];
} else {
$page=1;
}

// Page will start from 0 and Multiple by Per Page
$start_from = ($page-1) * $per_page;

//Selecting the data from table but with limit
$query = 'SELECT * FROM books LIMIT $start_from, $per_page';
$result = mysqli_query ($con, $query);
$total_records = mysqli_num_rows($result);
$total_pages = ceil($total_records / $per_page);

while ($row = mysqli_fetch_assoc($result)) {
$book_id = $row["id"];
$book_cover = $row["cover"];
$book_title = $row["title"];
$book_auther1 = $row["auther1"];                                  
$book_auther2 = $row["auther2"];    

        echo "
        <div></div>
        <li>
        <div id='divborder'>
        <div id='header'>
        <a class='caption caption1'data-title='$data_title'  href='book/$book_id'><img src='$book_cover' alt='' class='headerBg' /></a>
        </div>
        </div>
        </li> ";

}

//pagination goes here:
echo "<center><a href='".htmlspecialchars($_SERVER["PHP_SELF"])."?page=1'>First Page</a>";
for ($i=1; $i<=$total_pages; $i++) {
echo "<a href='".htmlspecialchars($_SERVER["PHP_SELF"])."?page=".$i."'>".$i."</a>";
}
echo "<center><a href='".htmlspecialchars($_SERVER["PHP_SELF"])."?page=$total_pages'>Last Page</a>";
?>