php中的数组排列

我的问题是我不能按我想要的结构排列数组。 array1和array2是动态生成的。正如您在数组2中所看到的，它有一个与数组1相同的subject，这意味着，该元素位于subject cpe 305之下。id为5的阵列2中的所有元素都属于cpe 305的主题。与cpe 304的逻辑相同

阵列1:

Array
(
[0] => Array
    (
        [subjectid] => 5
        [subjectcode] => Cpe 305
    )

[1] => Array
    (
        [subjectid] => 4
        [subjectcode] => Cpe 304
    )

)

Array
(
[0] => Array
    (
        [subjectid] => 5
        [soid] => 1
        [socode] => A
        [sodesc] => Ability to apply knowledge of mathematics and science to solve engineering problems
    )

[1] => Array
    (
        [subjectid] => 5
        [soid] => 3
        [socode] => C
        [sodesc] => Ability to design a system, component, or process to meet the desired needs within realistic constraints such as economic, environmental, social, political, ethical, health and safety, manufacturability, and sustainability, in accordance to standards
    )

[2] => Array
    (
        [subjectid] => 5
        [soid] => 4
        [socode] => D
        [sodesc] => Ability to function on multidisciplinary teams
    )

[3] => Array
    (
        [subjectid] => 5
        [soid] => 5
        [socode] => E
        [sodesc] => Ability to identify, formulate, and solve engineering problems
    )

[4] => Array
    (
        [subjectid] => 5
        [soid] => 9
        [socode] => I
        [sodesc] => Recognition of the need for, and an ability to engage in life-long learning
    )

[5] => Array
    (
        [subjectid] => 4
        [soid] => 10
        [socode] => J
        [sodesc] => Knowledge of contemporary issues
    )

阵列2:

Array
(
[0] => Array
    (
        [subjectid] => 5
        [subjectcode] => Cpe 305
    )

[1] => Array
    (
        [subjectid] => 4
        [subjectcode] => Cpe 304
    )

)

Array
(
[0] => Array
    (
        [subjectid] => 5
        [soid] => 1
        [socode] => A
        [sodesc] => Ability to apply knowledge of mathematics and science to solve engineering problems
    )

[1] => Array
    (
        [subjectid] => 5
        [soid] => 3
        [socode] => C
        [sodesc] => Ability to design a system, component, or process to meet the desired needs within realistic constraints such as economic, environmental, social, political, ethical, health and safety, manufacturability, and sustainability, in accordance to standards
    )

[2] => Array
    (
        [subjectid] => 5
        [soid] => 4
        [socode] => D
        [sodesc] => Ability to function on multidisciplinary teams
    )

[3] => Array
    (
        [subjectid] => 5
        [soid] => 5
        [socode] => E
        [sodesc] => Ability to identify, formulate, and solve engineering problems
    )

[4] => Array
    (
        [subjectid] => 5
        [soid] => 9
        [socode] => I
        [sodesc] => Recognition of the need for, and an ability to engage in life-long learning
    )

[5] => Array
    (
        [subjectid] => 4
        [soid] => 10
        [socode] => J
        [sodesc] => Knowledge of contemporary issues
    )

)

输出（我想要的结构）

我尝试过的

这是我正在测试的代码。我在测试代码中只包含很少的数据

      $so = array();
      $exist = array();

         foreach ($this->subject as $key => $value) {
          foreach ($this->sodetails as $key2 => $value2) {
            if($value['subjectid'] === $value2['subjectid']){

              $exist = array(
                  "subjectid" => $value['subjectid'],
                  "details" =>array(
                    "soid" => $value2['soid']
                  )
              );
              array_push($so, $exist);
            }
          }
        }

---

与运行

mxn

次的循环/迭代不同，您可以做的是首先将

subjectid

作为

$arrray1

的键，并让自然PHP数组键处理完成这项工作

$new_array1 = array();
foreach($arrray1 as $item){
 $new_array1[$item['subjectcode']] = $item;
}

foreach($array2 as $desc){
 if(array_key_exists($desc['subjectid'],$new_array1){
  $new_array1[$desc['subjectid']]['desc'][] = $desc;
 }
}

---

这样，您只需进行

m+n

迭代。

您只需在返回数组中将subject作为键传递

 $exist = array();
            foreach ($this->subject as $key => $value) {
              foreach ($this->sodetails as $key2 => $value2) {
                if($value['subjectid'] === $value2['subjectid']){
                    $exist[$value['subjectid']]['subjectid'] = $value['subjectid'];
                    $exist[$value['subjectid']]['subjectcode'] = $value['subjectcode'];
                    $exist[$value['subjectid']]['sodetails'] = array(array('soid'=>$value2['soid']),array('socode'=>$value2['socode']));
                }
              }
            }

---

首先，您的输出数组不正确。一个数组不能有多个相同的索引，如“subjectid”、“subjectcode”。我们需要一个不同的索引。明智的做法是使用subjectid作为外部数组的索引

首先准备外部阵列，因为它是阵列1

foreach($this->subject as $key => $val){
    $myArray[$val['subjectid']]['subjectid'] => $val['subjectid'];
    $myArray[$val['subjectid']]['subjectcode'] => $val['subjectcode'];
}

现在迭代你的sodetails数组

foreach($this->sodetails as $key => $val){
    $temp['soid'] = $val['soid'];
    $temp['socode'] = $val['socode'];
    array_push($myArray[$val['subjectid']]['sodetails'], $temp);
}

---

还有其他的方法。但这是我的风格，我相信它会解决你的问题。

你试过写代码吗？让我们看看你在解决这个问题上的努力。