Php Coinbase API，正在尝试获取非对象的属性

我只是在摆弄coinbase api，现在发现了一个错误。基本上我是说如果事务成功，那么只需简单地回显事务id之类的信息，但我得到一个错误：下面是我代码中最重要的部分

$result = $coinbase->sendMoney($address, $amount, "Thank you for using nahtnam's Faucet! - Best Regards, nahtnam");
$address_success = $response->success ? 'true' : 'false';
$address_status = $response->transaction->status;
$address_id = $response->transaction->id;
$address_amount = $response->transaction->amount->amount;

这里也是我显示信息的地方

elseif(isset($response['success']) && $response['success'] == 'true') {
    echo '
    <div class="row">
    <div class="col-lg-12">
    <center>
    <div class="alert alert-dismissable alert-success">
    <button type="button" class="close" data-dismiss="alert">&times;</button>
    <strong>Your Bitcoins have been sent!</strong><br>We have successfully sent '.$amount.' to your Bitcoin Address: '.$address.'... Here is some more info on the transaction:<br>Address: '.$address.'<br> Amount: '.$amount.'<br>Transaction Id: '.$address_id.'<br> Transaction Status: '.$address_status.'<br>Thank you for using nahtnam\'s Coinbase faucet. You can come back in <strong>30 Minutes</strong> to claim more!</a>.
    </div>
    </center>
    </div>
    </div>
    ';
    }

---

谢谢你的帮助！：

首先，您的sendMoney调用存储在$result中，您正在引用一个名为$response的对象，该对象基于错误不存在。

很抱歉，刚才我自己解决了这个问题：您刚才说的。。。我叔叔帮我解决了这个问题。。。我刚刚将$result更改为$response。。。谢谢你的回答-