为什么这两个字符串在PHP中不相同?
这是我的密码:为什么这两个字符串在PHP中不相同?,php,Php,这是我的密码: $city = $_GET['city']; $cityfinal = htmlentities($city, ENT_QUOTES | ENT_IGNORE, "UTF-8"); similar_text($cityfinal, "CITY OF BIÑAN", $percent); echo "Differnce between " . $cityfinal . " and CITY OF BIÑAN is " . $percent; 结果: 比尼安市和比尼安市之间
$city = $_GET['city'];
$cityfinal = htmlentities($city, ENT_QUOTES | ENT_IGNORE, "UTF-8");
similar_text($cityfinal, "CITY OF BIÑAN", $percent);
echo "Differnce between " . $cityfinal . " and CITY OF BIÑAN is " . $percent;
结果:
比尼安市和比尼安市之间的差异为72.7273
您的比较字符串未转换为htmlentities,因此它会给您带来差异。尝试转换它并检查 在这里,特殊字符BIña编码在$_GET['city']字符串中,但与给定的比较字符串保持一致
$city = $_GET['city'];
$checkcity ="CITY OF BIÑAN";
$cityfinal = htmlentities($city, ENT_QUOTES | ENT_IGNORE, "UTF-8");
$cityCheckwith = htmlentities($checkcity, ENT_QUOTES | ENT_IGNORE, "UTF-8");
similar_text($cityfinal, $cityCheckwith, $percent);
echo "Differnce between " . $cityfinal . " and CITY OF BIÑAN is " . $percent;
输出
边市和碧安市之间的差异为100
查看在线演示:您想要什么??百分比为0??字符编码为&xD1;这意味着BI&xD1;AN和BIñAN的城市不一样,如何才能在这一点上取得成果,对不起,我是php新手$结果=mysql_query从操作中选择不同的barangay,其中省份='$province'和城市='$cityfinal'按barangay排序;使用上面的代码,它工作明确,并满足您的期望@Kacey Manalact我问这个问题的原因是因为我在查询中得到了一个空结果:$result=mysql\u querySELECT DISTINCT barangay FROM operations,其中provides='$provider'和cities='cityfinal'由barangay排序;尝试使用LIKE:$result=mysql\u query从操作中选择不同的barangay,其中省份(如%'$province')和城市(如%'$cityfinal')按barangayTry排序以使用trim,并使用$province和$cityfinal数据粘贴查询。是的,当我在数据库中执行此操作时,我会得到我想要的结果,从barangay的操作中选择不同的barangay,其中省份='LAGUNA'和城市='CITY OF BIñAN'顺序,但出于某种原因,$_getwithñ字符做了一些不寻常的事情。