Php 查询数据库时接收错误

Php 查询数据库时接收错误,php,mysql,html,twitter-bootstrap-3,wamp,Php,Mysql,Html,Twitter Bootstrap 3,Wamp,我正在尝试为我的网站创建一个登录表单,其中用户名和密码已经存储在mydb中的user表中。我已经创建了checklogin.php来创建从我的网站到mydb的连接,然后检查登录的凭据 以下是checklogin.php的代码: <?php $host="127.0.0.1:3306"; // host name $username="root"; // mysql usrname $password=""; // mysql password $db_name="mydb"; // db

我正在尝试为我的网站创建一个登录表单,其中用户名和密码已经存储在mydb中的user表中。我已经创建了checklogin.php来创建从我的网站到mydb的连接,然后检查登录的凭据

以下是checklogin.php的代码:

<?php
$host="127.0.0.1:3306"; // host name
$username="root"; // mysql usrname
$password=""; // mysql password
$db_name="mydb"; // db name
$tbl_name="user"; // table name

//Connect to server and select database
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db("$db_name")or die(mysql_error());

//User name and password sent from form
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];

$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);

if($count==1)
{   // register $myusername, $mypassword and redirect file to loginSuc.php
    session_register("myusername");
    session_register("mypassword");
    header("location:loginSuc.php");
}
else 
{
    echo "wrong username or password";
}
?>

以下是表格(我使用了html5和twitter引导网格代码):


用户名
密码
登录

您应该为
mysql\u select\u db
使用变量名,而不是文字字符串

$host="127.0.0.1:3306"; // host name
$username="root"; // mysql usrname
$password=""; // mysql password
$db_name="mydb"; // db name
$tbl_name="user"; // table name

//Connect to server and select database
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db($db_name)or die(mysql_error()); // <-- $db_name instead of 'db_name'

//User name and password sent from form
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];

$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);

if($count==1)
{   // register $myusername, $mypassword and redirect file to loginSuc.php
    session_register("myusername");
    session_register("mypassword");
    header("location:loginSuc.php");
}
else 
{
    echo "wrong username or password";
}
$host=“127.0.0.1:3306”//主机名
$username=“root”//mysql usrname
$password=“”;//mysql密码
$db_name=“mydb”;//数据库名
$tbl_name=“用户”//表名
//连接到服务器并选择数据库
mysql_connect(“$host”、“$username”、“$password”)或die(“无法连接”);

mysql_选择_db($db_name)或die(mysql_error());// 这里的
db\u name
应该是
$db\u name

 mysql_select_db($db_name)or die(mysql_error());

我认为这应该行得通

<?php
$host="127.0.0.1:3306"; // host name
$username="root"; // mysql usrname
$password=""; // mysql password
$db_name="mydb"; // db name
$tbl_name="user"; // table name

//Connect to server and select databasemysql_connect
mysql_connect($host, $username, $password, $db_name) or die(mysql_error());

//execute when form is submit
if($_POST)
{   //set send data into variables
    $myusername=$_POST['myusername'];
    $mypassword=$_POST['mypassword'];

//check if username have been set
    if(is_null($myusername) || empty($myusername))
    {  $alert = "Enter something!";
    }
    else if(isset($myusername))
    {    $sql="SELECT * FROM ".$tbl_name." WHERE username=".$myusername." and password=".$mypassword;
        $result=mysql_query($sql);

    //convert data into array
        $data = mysql_fetch_array($result);
    //check if array is not empty
        if($data)
        {   //goto this line if user exist
            //set or register `$myusername` to variable `username` in session
            $_SESSION['myusername']=$myusername;

            header("location:loginSuc.php");
        }
        else 
        {   $alert = "wrong username or password"; }
    }
}
?>

我想你忘了$on
db\u name
mysql\u select\u db(“db\u name”)
您的
$\u POST
数组显然缺少触发错误的
myusername
字段。您需要在脚本开始时使用
var\u dump($\u post)
检查哪些帖子数据到达了您的脚本。一些好问题的提示:首先,请用标题描述问题,并避免诸如“请帮助”、“谢谢”等闲聊消息。它们在问题中通常是多余的。此外,这个问题在它的生命周期中发生了很大的变化,因为你已经解决了一件事和另一件事,所以现在可能太局部化了,对其他任何人都没有帮助。如果你可以每个问题保留一个问题,这会增加对其他有相同问题的读者有用的可能性。谢谢大家的快速修复,我现在在第13行有更多的问题,14和19关于如何解决这些问题,你有什么想法吗?那么请用你的其他问题更新原始问题。恐怕你只能指望在你的问题上得到帮助,这不包括性;)我只是注意到了那个错误,还没来得及改变它!抱歉哈,这只是一个旁注,当你在原始帖子中添加信息时,不要删除原始内容,只需在帖子底部添加你必须添加的内容即可。否则,它会使那些没有机会阅读原始问题的人感到困惑。这一次您可以保持原样。感谢您的评论,不幸的是,这在第12行出现了错误:注意:未定义变量:C:\wamp\www\HTML 5中的myusername,CSS 3&PHP\checklogin.PHP在第12行,注意:未定义变量:C:\wamp\www\HTML 5中的mypassword,第12行的CSS 3&PHP\checklogin.PHP将sql更改为
SELECT*FROM$tbl_name WHERE username=“..$myusername.”和password=“..$mypassword;”
我现在在第21行有另一个错误解析错误:语法错误,C:\wamp\www\HTML 5中的意外T_变量,第21行的CSS 3&PHP\checklogin.PHP是SELECT*FROM$tbl_name WHERE username=”.$myusername.”和password=“.$mypassword;等待您的表名错误。使用我应用于变量username的相同方法。你还在使用旧代码还是新代码来提供额外的保护?我正在使用你在上面添加的代码,并根据注释进行了更正,但现在我得到了“解析错误:语法错误,C:\wamp\www\HTML 5,CSS 3&PHP\checklogin.PHP中的意外T_变量,第12行是$sql=SELECT*from$tbl_name WHERE username”=“$myusername.”和password=“..$mypassword”;
<form class="form-horizontal" method="post" action="checklogin.php">
    <div class="form-group">
        <label for="myusername" class="control-label col-xs-3">Username</label>
        <div class="col-xs-6">
            <input type="text" class="form-control" id="myusername" placeholder="Library card number">
        </div>
    </div>
    <div class="form-group">
        <label for="mypassword" class="control-label col-xs-3">Password</label>
        <div class="col-xs-6">
            <input type="password" class="form-control" id="mypassword" placeholder="Password">
        </div>
    </div>
    <div class="form-group">
        <div class="col-xs-6">
        </div>
    </div>
    <div class="form-group">
        <div class="col-xs-offset-2 col-xs-24">
            <button type="submit" class="btn btn-primary">Login</button>
        </div>
    </div>
</form> 
$host="127.0.0.1:3306"; // host name
$username="root"; // mysql usrname
$password=""; // mysql password
$db_name="mydb"; // db name
$tbl_name="user"; // table name

//Connect to server and select database
mysql_connect("$host", "$username", "$password")or die("cannot connect");
mysql_select_db($db_name)or die(mysql_error()); // <-- $db_name instead of 'db_name'

//User name and password sent from form
$myusername=$_POST['myusername'];
$mypassword=$_POST['mypassword'];

$sql="SELECT * FROM $tbl_name WHERE username='$myusername' and password='$mypassword'";
$result=mysql_query($sql);

if($count==1)
{   // register $myusername, $mypassword and redirect file to loginSuc.php
    session_register("myusername");
    session_register("mypassword");
    header("location:loginSuc.php");
}
else 
{
    echo "wrong username or password";
}
 mysql_select_db($db_name)or die(mysql_error());
<?php
$host="127.0.0.1:3306"; // host name
$username="root"; // mysql usrname
$password=""; // mysql password
$db_name="mydb"; // db name
$tbl_name="user"; // table name

//Connect to server and select databasemysql_connect
mysql_connect($host, $username, $password, $db_name) or die(mysql_error());

//execute when form is submit
if($_POST)
{   //set send data into variables
    $myusername=$_POST['myusername'];
    $mypassword=$_POST['mypassword'];

//check if username have been set
    if(is_null($myusername) || empty($myusername))
    {  $alert = "Enter something!";
    }
    else if(isset($myusername))
    {    $sql="SELECT * FROM ".$tbl_name." WHERE username=".$myusername." and password=".$mypassword;
        $result=mysql_query($sql);

    //convert data into array
        $data = mysql_fetch_array($result);
    //check if array is not empty
        if($data)
        {   //goto this line if user exist
            //set or register `$myusername` to variable `username` in session
            $_SESSION['myusername']=$myusername;

            header("location:loginSuc.php");
        }
        else 
        {   $alert = "wrong username or password"; }
    }
}
?>
<form class="form-horizontal" method="post" action="checklogin.php">
    <div class="alert">
    <?php 
        if(isset($alert))
        {   echo $alert; }
    ?>
    </div>
    <div class="form-group">
        <label for="myusername" class="control-label col-xs-3">Username</label>
        <div class="col-xs-6">
            <input type="text" class="form-control" id="myusername" placeholder="Library card number" name="myusername">
        </div>
    </div>
    <div class="form-group">
        <label for="mypassword" class="control-label col-xs-3">Password</label>
        <div class="col-xs-6">
            <input type="password" class="form-control" id="mypassword" placeholder="Password" name="mypassword">
        </div>
    </div>
    <div class="form-group">
        <div class="col-xs-6">
        </div>
    </div>
    <div class="form-group">
        <div class="col-xs-offset-2 col-xs-24">
            <button type="submit" class="btn btn-primary">Login</button>
        </div>
    </div>
</form>