Php 我无法定义用于更新数据库的变量
代码如下:Php 我无法定义用于更新数据库的变量,php,Php,代码如下: <?php include "../include/koneksi_db.php"; include "../user/link.php"; $query=mysql_query("SELECT * FROM admin WHERE id=$id", $konek); $hasil=mysql_fetch_array($query); $id =$hasil['id']; $user=$hasil['username']; $pass=$hasil['passwor
<?php
include "../include/koneksi_db.php";
include "../user/link.php";
$query=mysql_query("SELECT * FROM admin WHERE id=$id", $konek);
$hasil=mysql_fetch_array($query);
$id =$hasil['id'];
$user=$hasil['username'];
$pass=$hasil['password'];
$hak =$hasil['hak_akses'];
?>
问题:
如何修复此问题:第5行的C:..\ed_user.php中的noticce:Undefined Variable:id不确定我是否理解正确:这是什么
<?php
include "../include/koneksi_db.php";
include "../user/link.php";
$check_the_query = "SELECT * FROM admin WHERE id='".$id."'";
$query=mysql_query(, $konek);
while($hasil=mysql_fetch_array($query)){
$id =$hasil['id'];
$user=$hasil['username'];
$pass=$hasil['password'];
$hak =$hasil['hak_akses'];
echo "id -> ".$id."<br>";
echo "user -> ".$id."<br>";
echo("<br>");
}
?>
$id=5;mysql\u querySELECT*FROM admin WHERE id=$id你在找这样的东西吗?你的问题是什么?什么不管用?你们对反对票要温和,OP显然是个英语知识不多的孩子。