Php 如何分配？

在数据库中，它是5342324223423，2423424242234234

还有我想做的

$capture_field_vals ="";
foreach($_POST["mytext"] as $key => $text_field)
{
   $capture_field_vals .= $text_field .", ";
}   
$insert = "INSERT INTO tabel1(numbers) VALUES('$capture_field_vals')";

然后

---

若DB中有动态字段，则表示字段数等于POST变量中数组的大小，则此代码适用于您

$insert2 = "INSERT INTO tabel2(number1, number2, number3, number4)  VALUES('$capture_field_vals[0]','$capture_field_vals[1]','$capture_field_vals[2]','$capture_field_vals[3]')";  

然后将执行insert查询

$capture_field_vals = $capture_fields = "";
$count = 1;
foreach($_POST["mytext"] as $key => $text_field) {
if ($capture_field_vals != "") {
    $capture_field_vals .= ", ";
}
if ($capture_fields != "") {
    $capture_fields .= ", ";
}
$capture_fields .= "number".$count;
$capture_field_vals .= $text_field;
$count++;
}

---

请描述更多。。您面临哪些问题阵列声明。。。首都。。。我用了和问题相同的第二部分，这样他就可以很快地实现我第一次在stackoverflow，我怎么能接受答案，为什么我不能投票支持这个答案没问题@Erki。。提前享受乐趣和精彩的编码-

$insert2 = "INSERT INTO tabel2(number1, number2, number3, number4)  VALUES('$capture_field_vals[0]','$capture_field_vals[1]','$capture_field_vals[2]','$capture_field_vals[3]')";  

$capture_field_vals = $capture_fields = "";
$count = 1;
foreach($_POST["mytext"] as $key => $text_field) {
if ($capture_field_vals != "") {
    $capture_field_vals .= ", ";
}
if ($capture_fields != "") {
    $capture_fields .= ", ";
}
$capture_fields .= "number".$count;
$capture_field_vals .= $text_field;
$count++;
}

$insert2 = "INSERT INTO tabel2(".$capture_fields.") VALUES (".$capture_field_vals.")";