mysql_num_行从php函数返回0值

我的script.php中有这个函数 $email=$_会话['cspa']['email']

    function getit()
    {
      $get_pendingsupport=mysql_query("select
    cus.email,
    datetime,
    s.service_type,
    subject,
    support_id,
    status,
    u.urgency
    from tbl_client_support c
    inner join tbl_client_service s on c.service_id=s.service_id
    inner join customer_reg cus on c.customer_reg_id=cus.id
    inner join tbl_client_urgency u on c.urgency_id=u.urgency_id

    where status='open'
    and cus.email='$email';

    ") or  die(mysql_error());

     return mysql_num_rows($get_pendingsupport) ;
    }
 that my function and am calling it like this in home.php

但它返回0作为值 但是当我把它带到home.php时，它就没事了

---

请找出可能的错误

它返回零，因为返回了零行。为什么？因为您从未将

$email

传递给您的函数，因此它不可用于您的查询。由于它在

WHERE

子句中使用，您的查询不会返回您认为会返回的行，因为没有任何行的状态为“打开”且客户电子邮件字段为空

可以通过将该变量传递给函数来解决此问题：

function getit($email)
{

当你称之为：

$num_rows = getit($email);

---

您没有将$email传递给查询。试试这个：

function getit($email)
    {
      $get_pendingsupport=mysql_query("select
    cus.email,
    datetime,
    s.service_type,
    subject,
    support_id,
    status,
    u.urgency
    from tbl_client_support c
    inner join tbl_client_service s on c.service_id=s.service_id
    inner join customer_reg cus on c.customer_reg_id=cus.id
    inner join tbl_client_urgency u on c.urgency_id=u.urgency_id

    where status='open'
    and cus.email='$email';

    ") or  die(mysql_error());

     return mysql_num_rows($get_pendingsupport) ;
    }

---

坦克这么多，它的工作有点享受这个论坛u摇滚