Php Reportico-报告参数传递

请帮助我通过PHP代码将报告参数传递给“Reportica report”

这是我尝试过的方法：

PHP代码：

require_once('../reportico/reportico.php'); 

$q = new reportico();

$q->initial_project = "loansys";
$q->initial_project_password = "k013";
$q->initial_report = "loansys.xml";
$q->initial_output_format = "HTML";
$q->embedded_report = true;

$q->allow_debug = true;
$q->forward_url_get_parameters = "";
$q->external_param1 = 1; 
$q->execute($q->get_execute_mode(), true);

报表查询：

SELECT l_number,due_number,due_date,amount,capital,interest
FROM  loan_due
WHERE l_number = {external_param1}

错误消息：

错误：连接错误（1064）：您的SQL语法有错误；检查与MySQL服务器版本对应的手册，以获取第3行“}）”附近使用的正确语法

我的剧本：

        require_once('../reportico/reportico.php'); 
        $q = new reportico();
        $q->initial_project = "xxxx";
        $q->initial_project_password = "xxxx";
        $q->initial_report = "xxxx.xml";
        $q->initial_execute_mode = "MENU";
        $q->access_mode = "SInGLEPROJECT";
        $q->embedded_report = true;
        $q->user_parameters["lnumber"] =  $_POST['cmblnumber'];
        $q->execute();

My reportico查询：

select 
    l_number, due_number, due_date, amount, capital, interest
from 
    loan_due
where
    l_number = "{USER_PARAM,lnumber}"
limit 
    0, 30

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它给了你这个问题。。{external_param1}无效。。这应该是什么？