php preg match仅获取最后匹配的字符串

我需要获取最后一个HTTP头。我的字符串是：

HTTP/1.1 302 Moved Temporarily
Date: Sat, 30 Apr 2016 09:48:56 GMT
Server: Apache
X-Powered-By: PHP/5.5.34
Location: 2.php
Content-Length: 0
Content-Type: text/html

HTTP/1.1 302 Moved Temporarily
Date: Sat, 30 Apr 2016 09:48:57 GMT
Server: Apache
X-Powered-By: PHP/5.5.34
Location: 3.php
Content-Length: 0
Content-Type: text/html

HTTP/1.1 200 OK
Date: Sat, 30 Apr 2016 09:48:57 GMT
Server: Apache
X-Powered-By: PHP/5.5.34
Transfer-Encoding: chunked
Content-Type: text/html

但我需要得到最后的标题。我试图用\n\n分解此字符串，但无法得到结果。可以用preg_match做吗？

明白了！ 我需要用以下代码将其分解：

explode("\r\n\r\n", $header);

---

使用

preg\u split

和

array\u pop

功能的解决方案：

// $headers is your initial string
$headers_splitted = preg_split("/\R{2}/", $headers);

print_r(array_pop($headers_splitted));

输出：

HTTP/1.1 200 OK
Date: Sat, 30 Apr 2016 09:48:57 GMT
Server: Apache
X-Powered-By: PHP/5.5.34
Transfer-Encoding: chunked
Content-Type: text/html