PHP代码。。。。查询之后，我需要更新表

我有一个过滤日期的查询，结果很好。但是在查询之后，我不知道如何更新要更改的表行

事情是这样的

<?php

if (isset($_POST['show'])){
    if (isset($_POST['startDate']))
    $startDate = strtoupper(trim(preg_replace("/[^0-9-]/", "", $_POST['startDate'])));// filter everything but spaces, numbers, and letters
    if (isset($_POST['dateEnd']))
    $dateEnd = strtoupper(trim(preg_replace("/[^0-9-]/", "", $_POST['dateEnd'])));// filter everything but spaces, numbers, and letters
$sql = mysql_query("SELECT * FROM enroll WHERE date >= '$startDate' AND date <= '$dateEnd' AND status = '0' ");
$DisplayList ="";
$enrollList = mysql_num_rows($sql);
if ($enrollList > 0) {
    while($row = mysql_fetch_array($sql)){
        $status = $row['status'];
        $amount = $row['en_amount'];
    if ($status == 0) 
        $st = 'NOT ENROLLED';
        else
        $st = 'ENROLLED';
        $DisplayList .= "<strong>$st</strong><br />";//output the list request
    }
} else {
    $DisplayList = "PLEASE INPUT VALID ENTRIES";
}
}
?>

---

像Fred-ii-说-使用更新查询：

$status = 1;
mysql_query("UPDATE enroll SET status = '$status' WHERE date >= '$startDate' AND date <= '$dateEnd' AND status = '0' ");

$status=1；
mysql\u查询("更新注册集状态=“$status”，其中日期>=“$startDate”和日期使用-从MySQL手册中，更新状态时，您希望得到什么结果？状态将在MySQL上更新为“1”或“已注册”，即下次我运行相同的日期范围时，更新的状态将不会显示为列表中的条件…噢，and我有一个按钮需要点击才能更新。我希望我能解释清楚。谢谢！）