Php 将结果与if/else语句混淆
这是到目前为止我的一些脚本：Php 将结果与if/else语句混淆,php,if-statement,Php,If Statement,这是到目前为止我的一些脚本： $check = ("SELECT username FROM users WHERE username = '$us3r'"); $check2 = ("SELECT password FROM users WHERE username = '$us3r'"); $check3 = ("SELECT userID FROM users WHERE username = '$us3r'"); $check4 = ("SELECT userrole FROM user
$check = ("SELECT username FROM users WHERE username = '$us3r'");
$check2 = ("SELECT password FROM users WHERE username = '$us3r'");
$check3 = ("SELECT userID FROM users WHERE username = '$us3r'");
$check4 = ("SELECT userrole FROM users WHERE username = '$us3r'");
//Role
$role = mysql_query($check4);
$arr5 = mysql_fetch_row($role);
$roles = ($arr5[0]);
echo $roles;
if($roles = 1) {
//Username
$results3 = mysql_query($check);
$arr2 = mysql_fetch_row($results3);
$results4 = ($arr2[0]);
//Password
$results5 = mysql_query($check2);
$arr3 = mysql_fetch_row($results5);
$results6 = ($arr3[0]);
//UID
$id1 = mysql_query($check3);
$arr4 = mysql_fetch_row($id1);
$id = ($arr4[0]);
echo 1;
}
else if($roles = 2) {
//Username
$mresults3 = mysql_query($check);
$marr2 = mysql_fetch_row($mresults3);
$mresults4 = ($marr2[0]);
//Password
$mresults5 = mysql_query($check2);
$marr3 = mysql_fetch_row($mresults5);
$mresults6 = ($arr3[0]);
//UID
$mid1 = mysql_query($check3);
$marr4 = mysql_fetch_row($mid1);
$mid = ($marr4[0]);
echo 2;
};
但是，如果由于某种原因，当我使用用户角色为2的用户时，回显显示为21，则我希望它是11或22:///p>您需要使用
===如果您使用赋值（
====如果使用赋值（
==$rolesif($roles == 1) {
...
}
else if ($roles == 2) {
...
}
您正在设置
$rolesif($roles == 1) {
...
}
else if ($roles == 2) {
...
}
if($roles = 1) {
if($roles == 1) {
if($roles = 1) {
if($roles == 1) {
if($roles = 1)
else if($roles = 2)
if($roles = 1)
else if($roles = 2)
那么，有什么理由你不能这么做（没有
ifelse那么，有什么理由你不能这么做（没有
ifelseif$roles = ($arr5[0]);
if ($roles = 2) {
$rolesifif (($roles = $arr5[0]) == 2) {
$roles$a$bif$roles = ($arr5[0]);
if ($roles = 2) {
$rolesifif (($roles = $arr5[0]) == 2) {
$roles$a$b它必须只有几行，而不是两页
$us3r = mysql_real_escape_string($us3r);
$sql = "SELECT * FROM users WHERE username = '$us3r'";
$res = mysql_query($sql);
$userdata = mysql_fetch_assoc($role);
// now you have all user's data in the $userdata array.
// echo $userdata['username']; for example will echo a username
// no need for the separate queries, no need to write the same code twice.
// and, finally
echo $userdata['userrole'];
//it seems the only thing your code does - echoing the actual userrole value:
为了让您知道，您的整个代码毫无意义。
它必须只有几行，而不是两页
$us3r = mysql_real_escape_string($us3r);
$sql = "SELECT * FROM users WHERE username = '$us3r'";
$res = mysql_query($sql);
$userdata = mysql_fetch_assoc($role);
// now you have all user's data in the $userdata array.
// echo $userdata['username']; for example will echo a username
// no need for the separate queries, no need to write the same code twice.
// and, finally
echo $userdata['userrole'];
//it seems the only thing your code does - echoing the actual userrole value:
代码末尾的
；；