Php 相同格式的多维数组之和
我有一个多维数组,格式如下:Php 相同格式的多维数组之和,php,arrays,laravel,multidimensional-array,sum,Php,Arrays,Laravel,Multidimensional Array,Sum,我有一个多维数组,格式如下: array ( 0 => array ( 'manual' => 1, 'cancelled' => 1, 'expired' => 1, 'earned' => 1, 'user' => array ( 'user1' => 1, 'user2' => 1, 'user3' => 1, 'user4' =
array (
0 =>
array (
'manual' => 1,
'cancelled' => 1,
'expired' => 1,
'earned' => 1,
'user' =>
array (
'user1' => 1,
'user2' => 1,
'user3' => 1,
'user4' => 1,
),
'transfer' =>
array (
'transfer1' =>
array (
'key1' => 1,
'key2' => 1,
'key3' => 1,
),
'transfer2' =>
array (
'key5' => 1,
'key6' => 1,
'key7' => 1,
),
),
'date' => '2018-03-07',
),
1 =>
array (
'manual' => 1,
'cancelled' => 1,
'expired' => 1,
'earned' => 1,
'user' =>
array (
'user1' => 1,
'user2' => 1,
'user3' => 1,
'user4' => 1,
),
'transfer' =>
array (
'transfer1' =>
array (
'key1' => 1,
'key2' => 1,
'key3' => 1,
),
'transfer2' =>
array (
'key5' => 1,
'key6' => 1,
'key7' => 1,
),
),
'date' => '2018-03-08',
),
)我需要计算具有相同索引的数组值之和。因此,总数组应如下所示
Array
(
[total] => Array
(
[manual] => 2
[cancelled] => 2
[expired] => 2
[earned] => 2
[user] => Array
(
[user1] => 2
[user2] => 2
[user3] => 2
[user4] => 2
)
[transfer] => Array
(
[transfer1] => Array
(
[key1] => 2
[key2] => 2
[key3] => 2
)
[transfer2] => Array
(
[key5] => 2
[key6] => 2
[key7] => 2
)
)
也就是说,除了日期之外,合计应该具有相同的格式,但它需要显示值的总和。如何在PHP中实现这一点?我使用了以下代码
$final = array_shift($input);
foreach ($final as $key => &$value){
$value += array_sum(array_column($input, $key));
}
unset($value);
var_dump($final);
其中,
$input
被视为第一个数组,$final
是总计。我认为这只适用于单个索引 可以使用递归函数遍历所有“树”
那里
若元素为数组,则在结果数组中创建相同的元素,并为每个键运行函数。
若它有一个数字,只需在结果中添加值即可
这是一个样本
<?php
// Array with data
$arr=array(array('manual'=>1,'cancelled'=>1,'expired'=>1,'earned'=>1,'user'=>array('user1'=>1,'user2'=>1,'user3'=>1,'user4'=>1,),'transfer'=>array('transfer1'=>array('key1'=>1,'key2'=>1,'key3'=>1,),'transfer2'=>array('key5'=>1,'key6'=>1,'key7'=>1,)),'date'=>'2018-03-07',),array('manual'=>1,'cancelled'=>1,'expired'=>1,'earned'=>1,'user'=>array('user1'=>1,'user2'=>1,'user3'=>1,'user4'=>1,),'transfer'=>array('transfer1'=>array('key1'=>2,'key2'=>2,'key3'=>2,),'transfer2'=>array('key5'=>2,'key6'=>2,'key7'=>2,)),'date'=>'2018-03-08',));
//Init result array
$res=array('total'=>array());
foreach ($arr as $key=>$val) {
//Run it for each element and store result to $res['total']
countTotal($res['total'],$val);
}
//Show result
print_r($res);
/*
* Count totals for branch of array
* @param $res - reference to branch of result array
* @param $arr - branch of data array
*/
function countTotal(&$res,$arr) {
foreach ($arr as $key=>$val) {
if (is_array($val)) {
//it's array. Create "branch" in $res and run countTotal() to calc total for it
if (!isset($res[$key])) $res[$key]=array();
countTotal($res[$key],$val);
} else if (is_numeric($val)) {
// it's number. Create "leaf" if need and add value.
if (!isset($res[$key])) $res[$key]=0;
$res[$key]+=$val;
}
}
}
在第二个“transfer”中,我使用了“2”,所以它的总和是“3”您可以编写如下递归函数:
function array_sum_recursive_assoc($array, &$result = [])
{
$keys = array_keys($array[0] ?? []);
foreach ($keys as $key) {
foreach (($column = array_column($array, $key)) as $value) {
if (is_array($value)) {
$result[$key] = [];
array_sum_recursive_assoc($column, $result[$key]);
continue 2;
}
// In this case date safe guard.
if (!is_numeric($value)) {
continue;
}
$result[$key] = ($result[$key] ?? 0) + $value;
}
}
return $result;
}
var_dump(array_sum_recursive_assoc($array));
这是。
相同的索引。
->您用来比较的索引是什么?@AlivetoDie第0个元素中的索引手动
需要添加到第一个元素中的手动
。因此,手动
索引的总值为2。这对所有其他索引都是一样的。所以根据手册,您将检查是否需要添加子数组?我说的对吗?你可以在这里找到解决办法不。这就像$total['total']['manual']=$array[0]['manual']+$array[1]['manual']
和$total['total']['cancelled']=$array[0]['cancelled']+$array[1]['cancelled']
和$total['total']['user'['user1']=$array[0]['user']['user1']+$array[1]//code>
function array_sum_recursive_assoc($array, &$result = [])
{
$keys = array_keys($array[0] ?? []);
foreach ($keys as $key) {
foreach (($column = array_column($array, $key)) as $value) {
if (is_array($value)) {
$result[$key] = [];
array_sum_recursive_assoc($column, $result[$key]);
continue 2;
}
// In this case date safe guard.
if (!is_numeric($value)) {
continue;
}
$result[$key] = ($result[$key] ?? 0) + $value;
}
}
return $result;
}
var_dump(array_sum_recursive_assoc($array));