HTML和PHP嵌入
这里我试图从mysql表中获取数据并将其填充到html中。一切正常,但我想通过一个IF条件回显一个html按钮。我不知道这是否行得通如果行得通谁能告诉我怎么做?。我得到的错误是…内部服务器错误:( 注意:我已经指出了我遇到问题的确切位置HTML和PHP嵌入,php,javascript,mysql,html,Php,Javascript,Mysql,Html,这里我试图从mysql表中获取数据并将其填充到html中。一切正常,但我想通过一个IF条件回显一个html按钮。我不知道这是否行得通如果行得通谁能告诉我怎么做?。我得到的错误是…内部服务器错误:( 注意:我已经指出了我遇到问题的确切位置 <?php if(mysql_num_rows($sql)){ while($rs = mysql_fetch_object($sql)) { ?> <tr> <t
<?php
if(mysql_num_rows($sql)){
while($rs = mysql_fetch_object($sql))
{
?>
<tr>
<td align="center"><?php echo $rs->cnf_name ;?></td>
<td align="center"><?php echo $rs->address;?></td>
<td align="center"><?php echo $rs->added_on;?></td>
<td align="center"><input type="button" class="btn" value="Edit" onClick="window.parent.editCnf('<?php echo $rs->cnf_name;?>','<?php echo $rs->username ;?>','<?php echo $rs->password;?>','<?php $rs->type;?>','<?php echo $rs->person_name;?>','<?php echo $rs->address;?>','<?php echo $rs->mobile_no?>','<?php echo $rs->email;?>','<?php echo $rs->country;?>','<?php echo $rs->city;?>','<?php echo $rs->state;?>','<?php echo $rs->area;?>')" ></td>
//PROBLEM
<td align="center">
<?php
if($rs->cnf_status == 0)
{
echo "<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf(<?php echo $rs->user_id;?>,<?php echo $rs->cnf_status; ?>);">";
}
else
{
echo "<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf(<?php echo $rs->user_id;?>,<?php echo $rs->cnf_status; ?>);">";
}
?>
</td>
</tr>
<?php
}
}
else
{
?> <tr>
<td colspan="">No data to display</td>
</tr>
<?php
}
?>
</tbody>
</table>
问题在于你的语法。你必须在你的回音中转义:
<?php
if($rs->cnf_status == 0)
{
echo "<input type=\"button\" class=\"btn\" id=\"status\" value=\"Activate\" onClick=\"window.parent.deleteCnf({$rs->user_id}, {$rs->cnf_status});\">";
}
else
{
echo "<input type=\"button\" class=\"btn\" id=\"status\" value=\"Activate\" onClick=\"window.parent.deleteCnf({$rs->user_id}, {$rs->cnf_status});\">";
}
?>
或
问题出在你的语法上。你必须在回声中转义:
<?php
if($rs->cnf_status == 0)
{
echo "<input type=\"button\" class=\"btn\" id=\"status\" value=\"Activate\" onClick=\"window.parent.deleteCnf({$rs->user_id}, {$rs->cnf_status});\">";
}
else
{
echo "<input type=\"button\" class=\"btn\" id=\"status\" value=\"Activate\" onClick=\"window.parent.deleteCnf({$rs->user_id}, {$rs->cnf_status});\">";
}
?>
或
问题来自于echo使用的引号;
要么去
echo 'htmlcode_with_doublequotes';
或
if($rs->cnf_状态==0)
{
?>
","");">
","");">
问题来自于echo使用的引号;
要么去
echo 'htmlcode_with_doublequotes';
或
if($rs->cnf_状态==0)
{
?>
","");">
","");">
这似乎是html按钮回音中引号的问题
if($rs->cnf_status == 0)
{
echo '<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf(<?php echo $rs->user_id;?>,<?php echo $rs->cnf_status; ?>);">';
}
else
{
echo '<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf(<?php echo $rs->user_id;?>,<?php echo $rs->cnf_status; ?>);">';
}
if($rs->cnf_状态==0)
{
echo'这似乎是html按钮echo中的引号有问题
if($rs->cnf_status == 0)
{
echo '<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf(<?php echo $rs->user_id;?>,<?php echo $rs->cnf_status; ?>);">';
}
else
{
echo '<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf(<?php echo $rs->user_id;?>,<?php echo $rs->cnf_status; ?>);">';
}
if($rs->cnf_状态==0)
{
echo'试试这个:
<?php
if($rs->cnf_status == 0)
{
echo '<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf('.$rs->user_id.','.$rs->cnf_status.');">';
}
else
{
echo '<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf('.$rs->user_id.','.$rs->cnf_status.');">';
}
?>
试试这个:
<?php
if($rs->cnf_status == 0)
{
echo '<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf('.$rs->user_id.','.$rs->cnf_status.');">';
}
else
{
echo '<input type="button" class="btn" id="status" value="Activate" onClick="window.parent.deleteCnf('.$rs->user_id.','.$rs->cnf_status.');">';
}
?>