将JSON值转换为PHP字符串
需要从GoogleMapsAPI获取值“distance”“text”,并将其转换为PHP字符串 例如,它给了我们:将JSON值转换为PHP字符串,php,json,google-maps,google-maps-api-3,Php,Json,Google Maps,Google Maps Api 3,需要从GoogleMapsAPI获取值“distance”“text”,并将其转换为PHP字符串 例如,它给了我们: { "destination_addresses" : [ "New Town, Uckfield, East Sussex TN22 5DJ, UK" ], "origin_addresses" : [ "Maresfield, East Sussex TN22 2AF, UK" ], "rows" : [ { "elements
{
"destination_addresses" : [ "New Town, Uckfield, East Sussex TN22 5DJ, UK" ],
"origin_addresses" : [ "Maresfield, East Sussex TN22 2AF, UK" ],
"rows" : [
{
"elements" : [
{
"distance" : {
"text" : "3.0 mi",
"value" : 4855
},
"duration" : {
"text" : "22 mins",
"value" : 1311
},
"status" : "OK"
}
]
}
],
"status" : "OK"
}
如何将值“3.0 mi”从这个JSON提要更改为PHP变量
非常感谢 是你的朋友,回答:)
谢谢多莉·齐登,我最终实现了这一目标,解决了我的问题:
<?php
$q = "https://maps.googleapis.com/maps/api/distancematrix/json?origins=TN222AF&destinations=tn225dj&mode=bicycling&language=gb-FR&sensor=false&units=imperial";
$json = file_get_contents($q);
$details = json_decode($json);
$distance=$details->rows[0]->elements[0]->distance->text;
echo $distance;
?>
$json=
$json = <<<END_OF_JSON
{
"destination_addresses" : [ "New Town, Uckfield, East Sussex TN22 5DJ, UK" ],
"origin_addresses" : [ "Maresfield, East Sussex TN22 2AF, UK" ],
"rows" : [
{
"elements" : [
{
"distance" : {
"text" : "3.0 mi",
"value" : 4855
},
"duration" : {
"text" : "22 mins",
"value" : 1311
},
"status" : "OK"
}
]
}
],
"status" : "OK"
}
END_OF_JSON;
$arr = (json_decode($json, true));
echo $arr["rows"][0]["elements"][0]["distance"]["text"];
--output:--
3.0 mi