Php 无法获取symfony2中上载文件的文件名
我使用Symfony2跟踪了多个文件上传,并创建了一个实体Php 无法获取symfony2中上载文件的文件名,php,symfony,upload,Php,Symfony,Upload,我使用Symfony2跟踪了多个文件上传,并创建了一个实体 /* * @ORM\HasLifecycleCallbacks * @ORM\Entity(repositoryClass="Repair\StoreBundle\Entity\attachmentsRepository") */ class attachments { /** * @var integer * * @ORM\Column(name="id", type="integer"
/*
* @ORM\HasLifecycleCallbacks
* @ORM\Entity(repositoryClass="Repair\StoreBundle\Entity\attachmentsRepository")
*/
class attachments
{
/**
* @var integer
*
* @ORM\Column(name="id", type="integer")
* @ORM\Id
* @ORM\GeneratedValue(strategy="AUTO")
*/
private $id;
/**
* @var string
*
* @Assert\File(maxSize="6000000")
* @ORM\Column(name="files", type="array", length=255, nullable=true)
*/
private $files=array();
/**
* Get id
*
* @return integer
*/
public function getId() {
return $this->id;
}
/**
* Set files
* @param object $files
*
* @return attachments
*/
public function setFiles($files) {
$this->files = $files;
}
/**
* Get files
*
* @return object
*/
public function getFiles() {
return $this->files;
}
public function __construct() {
$files = array();
}
public function uploadFiles() {
// the files property can be empty if the field is not required
if (null === $this->files) {
return;
}
if (!$this->id) {
$this->files->move($this->getTmpUploadRootDir(), $this->files->getClientOriginalName());
} else {
$this->files->move($this->getUploadRootDir(), $this->files->getClientOriginalName());
}
$this->setFiles($this->files->getClientOriginalName());
}
public function getAbsolutePath() {
return null === $this->path
? null
: $this->getUploadRootDir() . DIRECTORY_SEPARATOR . $this->path;
}
public function getWebPath() {
return null === $this->path
? null
: $this->getUploadDir() . DIRECTORY_SEPARATOR . $this->path;
}
protected function getUploadRootDir() {
return __DIR__ . '/../../../../web/'. $this->getUploadDir();
}
protected function getUploadDir() {
return 'uploads/';
}
}
我有一个控制器,其代码如下
class uploadController extends Controller
{
public function uploadAction(Request $request) {
$id= $_GET['id'];
$user = new attachments();
$form = $this->createFormBuilder($user)->add('files','file',array("attr"=>array("multiple" =>"multiple",)))->getForm();
$formView = $form->createView();
$formView->getChild('files')->set('full_name','form[file][]');
if ($request->getMethod() == 'POST') {
$em = $this->getDoctrine()->getManager();
$form->bind($request);
$files = $form["files"]->getFilenames();
$user->uploadFiles(); //--here iam not able to get te file names in order to send to the upload function.upload files is returning null values
}
}
}
控制器无法从视图中获取uder上载的文件名。当我发送到实体中的上载函数时,它返回空值。我认为您应该再次阅读。您正确地使用了注释
@ORM\HasLifecycleCallbacks
,但您的代码缺少方法的正确注释。您可以使用@ORM\PostPersist()
和@ORM\PostUpdate()
注释在验证请求并持久化对象后自动调用upload()
函数。我还建议为每个文件使用一个实体并创建一个关系。这将使正确存储文件变得更加容易和合乎逻辑。不清楚您的意思,除了代码,你能提供更多信息吗?我想上传多个文件。为此,我需要在尝试使用表单[“文件”]->getData()从控制器检索上传的文件时,获取用户从视图上传到控制器的文件名;当我传递$em=$this->getDoctrine()->getManager()时,它返回空值;在upload函数中,它返回空值,即无法将文件名从控制器传送到实体以便上载。在控制器本身中,它无法从视图中获取文件名