Php 选择计数组并使用键和值输出到数组中

我希望从数据库中选择

number\u id=1

的所有行，并将经验id分组，并将每个in的计数输出到一个数组中，其中experience

id

作为键，而

count

作为值

+------------+------------+
| number_id  | experience |
+------------+------------+
|  1         |  4         |
|  1         |  4         |
|  1         |  1         |
|  1         |  2         |
|  1         |  3         |
|  1         |  1         |
|  1         |  5         |
+------------+------------+

因此，结果应该是：

4 => 2
1 => 2
2 => 1
3 => 1
5 => 1

这就是我到目前为止所做的：

$query = "SELECT COUNT(*) AS SUM FROM comments WHERE number_id = '1' GROUP BY experience";

$result = mysqli_query($conn, $query);
$experience = array();
if ($result->num_rows>0) {
    while ($row = mysqli_fetch_assoc($result)) {
        $experience[] = $row['SUM'];
    }
}

print_r($experience);

哪个输出这个

Array ( [0] => 2 [1] => 2 [2] => 1 [3] => 1 [5] => 1 )

但我需要能够将它们的数组键更改为经验id

---

我怎样才能做到这一点呢？

只需选择

experience

并将其用作键即可

$query = "SELECT experience, COUNT(*) AS SUM FROM comments WHERE number_id = '1' GROUP BY experience";

$result = mysqli_query($conn, $query);
$experience = array();
if ($result->num_rows>0) {
    while ($row = mysqli_fetch_assoc($result)) {
        $experience[$row['experience']] = $row['SUM'];
    }
}

print_r($experience);

---

只需选择

experience

并将其用作键

$query = "SELECT experience, COUNT(*) AS SUM FROM comments WHERE number_id = '1' GROUP BY experience";

$result = mysqli_query($conn, $query);
$experience = array();
if ($result->num_rows>0) {
    while ($row = mysqli_fetch_assoc($result)) {
        $experience[$row['experience']] = $row['SUM'];
    }
}

print_r($experience);

array_列（mysqli_fetch_all（$result，mysqli_ASSOC），'sum'，'experience'）
array\u列（mysqli\u fetch\u all（$result，mysqli\u ASSOC），'sum'，'experience'）