PHP/MYSQL：更新数据不是'；不工作，请看一看
好的，我想创建一个更新表单，基本上更新表中的一条记录，但我不能这样做。我得到的错误如下：未定义的索引Id和所有。。这是我的密码。。我犯了什么错误PHP/MYSQL：更新数据不是'；不工作，请看一看,php,html,mysql,database,xampp,Php,Html,Mysql,Database,Xampp,好的，我想创建一个更新表单，基本上更新表中的一条记录，但我不能这样做。我得到的错误如下：未定义的索引Id和所有。。这是我的密码。。我犯了什么错误 <?php // PHP code to update data from MySQL database table if (isset($_POST['update'])) { $hostname = "localhost"; $username = "root"; $password = "";
<?php
// PHP code to update data from MySQL database table
if (isset($_POST['update'])) {
$hostname = "localhost";
$username = "root";
$password = "";
$databaseName = "winc sports";
$connect = mysqli_connect($hostname, $username, $password, $databaseName);
// get values form input text and number
$id = $_POST['Id'];
$fname = $_POST['Fname'];
$lname = $_POST['Lname'];
$age = $_POST['Age'];
$country=$_POST['Nationality'];
$phone=$_POST['PhoneNumber'];
$email=$_POST['Email'];
// mysql query to Update data
$query = "UPDATE `students` SET `Fname`='" . $fname . "',`Lname`='" . $lname . "',`Nationality`='" . $country . "',`PhoneNumber`=" . $phone . ",`Email`='".$email."',`Age`= " . $age . " WHERE `Id` = '" . $id . "'";
$result = mysqli_query($connect, $query);
if($result) {
echo 'Data Updated';
} else {
echo 'Data Not Updated';
}
mysqli_close($connect);
}
?>
<!DOCTYPE html>
<html>
<head>
<title>PHP INSERT DATA USING PDO</title>
<meta charset="UTF-8">
<meta name="viewport" content="width=device-width, initial-scale=1.0">
</head>
<body>
<form action="updating.php" method="post">
<input type="text" name="id" placeholder="Enter new ID"><br><br>
<input type="text" name="fname" placeholder="Enter new First Name"><br><br>
<input type="text" name="lname" placeholder="Enter new Last Name"><br><br>
<input type="number" name="age" placeholder="Enter new age" min="13" max="90"><br><br>
<input type="text" name="country" placeholder="Enter new Nationality"><br><br>
<input type="number" name="phone" placeholder="Enter new Phone Number"><br><br>
<input type="text" name="email" placeholder="Enter new Email"><br><br>
<input type="submit" name="update" value="update">
</form>
</body>
</html>
PHP使用PDO插入数据
尝试使用var_dump（$_POST）查看它实际包含的内容。您的表单正在发布
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