Php 如何在一个类中调用另一个类的扩展函数？

好的，我知道。我知道。。。这个可能很简单。但是，我对OOP非常陌生，希望学习如何更有效地回收代码

我在php中有一个类，然后是另一个类，它扩展了前面的类

class team {
   private $league;
   private $team;
   public $year = 2013;

   function getTeamSeasonRecord($league, $team) {
   // Get given's team record thus far

      $this->record = $record;
     return $record;
}

class game extends team{

  public function __construct()
  {
        global $db;

        if($game_league == "mlb")
        {
            $table = "current_season_games";
        } else
        {
            $table = "".$game_league."_current_season_games";
        }

        $query = "SELECT * FROM ".$table." WHERE game_id = :game_id";
        $stmt = $db->prepare($query);
        $stmt->execute(array(':game_id' => $game_num));
        $count = $stmt->rowCount();

        $this->games_count = $count;

        if($count == 1)
        {
            $this->game_league = $game_league;
            $this->game_num = $game_num;

            while($row = $stmt->fetch(PDO::FETCH_ASSOC)) 
            {
                $home_team  = $row['home_team'];
                $away_team  = $row['away_team'];
                $game_int   = $row['game_date_int'];
                $game_date  = $row['game_date'];
                $game_time  = $row['game_time'];
            }

            $this->home_team = $home_team;
            $this->away_team = $away_team;
            $this->game_int = $game_int;
            $this->game_date = $game_date;
            $this->game_time = $game_time;
        }
    }

  $team_class = new team($this->game_league, $this->home_team, 2013);
  $record = $team_class->getTeamSeasonRecord($this->game_league, $this->home_team);
  $this->team_record -> $record;
}

---

既然名为“game”的类是名为“team”的类的扩展，那么game类不能访问team类范围内的所有函数吗？在team类中编写的getTeamSeasonRecord（）函数将查找任何给定团队的记录。但是，对于游戏类，有两个团队。1）主队和2）客队。我需要找到主队和客队的记录。如何循环使用代码，使两个类中的函数都不必相同？

游戏不应扩展团队，因为游戏不是团队。一个游戏是由团队玩的，它是一个完全不同的对象，你所建模的继承方式不应该适用

class game{

  private $homeTeam;
  private $awayTeam;

  function GetHomeTeam()
  {
    return $this->homeTeam;
  }

  function GetAwayTeam()
  {
    return $this->awayTeam;
  }
}

一个可能使用继承的示例（并继续使用运动域）

---

SoccerTeam和BaseballTeam（子类型）都是团队（超类型），并且有一个赛季排名，但是他们必须扩展团队以实现团队所玩游戏的复杂性。

您建模的方式没有意义。一场比赛不是一个团队，所以你不应该扩大团队。但是一个游戏由两个团队组成。一个游戏由两个团队玩，它不由两个团队组成，所以你应该有完全独立的团队和游戏类，游戏类有homeTeam和awayTeam属性，这是团队类的实例OK。这是真的。我仍然不知道如何组织我的课程。我之所以将game类作为team类的扩展，是因为对于team类中的所有函数，大多数函数都需要应用于游戏中的两个团队？酷。谢谢我试试看。你能给我举个例子，说明什么时候一个对象应该是另一个对象的扩展吗？

class Team
{
  function GetSeasonRanking(){...}
}

class SoccerTeam extends Team
{
  function GetGoalKeeper(){...}
}

class BaseballTeam extends Team
{
  function GetPitchers{...}
}