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Php 将每个数组值返回到变量中_Php_Arrays - Fatal编程技术网

Php 将每个数组值返回到变量中

Php 将每个数组值返回到变量中,php,arrays,Php,Arrays,我想从如下数组中恢复所有值: $var = array($jogo1_t1, $jogo1_t2, $jogo2_t1, $jogo2_t2, $jogo3_t1, $jogo3_t2); 如何将每个值导出到不同的变量中 例如: $var1 = FIRST ARRAY VALUE $var2 = SECOND ARRAY VALUE $var3 = THIRD ARRAY VALUE 或使用: 或者简单地使用数组键: $var1 = $var[0]; $var2 = $var[1]; $va

我想从如下数组中恢复所有值:

$var = array($jogo1_t1, $jogo1_t2, $jogo2_t1, $jogo2_t2, $jogo3_t1, $jogo3_t2);
如何将每个值导出到不同的变量中

例如:

$var1 = FIRST ARRAY VALUE
$var2 = SECOND ARRAY VALUE
$var3 = THIRD ARRAY VALUE
或使用:

或者简单地使用数组键:

$var1 = $var[0];
$var2 = $var[1];
$var3 = $var[2];
$var4 = $var[3];
$var5 = $var[4];
$var6 = $var[5];
或者,如果必须,请使用动态变量名称(如果
$var
的大小不需要重写代码,则可以使用此名称):

for($i=0;$i
您需要列表():

$array=array($jogo1_t1、$jogo1_t2、$jogo2_t1、$jogo2_t2、$jogo3_t1、$jogo3_t2);

列表($var1,$var2)=$array

您为什么要这样做?列表($var1,$var2,$var3,$var4,$var5,$var6)=数组($jogo1_t1,$jogo1_t2,$jogo2_t1,$jogo2_t2,$jogo3_t1,$jogo3_t2);也许谢谢你!那正是我想要的!
$var1 = $var[0];
$var2 = $var[1];
$var3 = $var[2];
$var4 = $var[3];
$var5 = $var[4];
$var6 = $var[5];
for ($i = 0; $i < count($var); $i++) {
    $variableName = 'var' . ($i + 1);
    $$variableName = $var[$i];
}
$var1 = $var[0];
$var2 = $var[1];
$var3 = $var[2];
// ...etc