使用php进行JSON编码正在生成数组

我需要从数组生成一个编码的JSON字符串。但是，当我简单地从数组中取消设置一个项时，整个字符串的结构会变得非常不同

以该代码为例：

$temp1 = array();

$temp1[] = array("x" => "aaa", "y" => "bbb");
$temp1[] = array("x" => "ccc", "y" => "ddd");
$temp1[] = array("x" => "eee", "y" => "fff");

$encoded = json_encode($temp1);

echo $encoded;

它将输出：

[{x:aaa，y:bbb}，{x:ccc，y:ddd}，{x:eee，y:fff}]

当然，这是我所期望的！现在，请看下面这段非常类似的代码：

$temp1 = array();

$temp1[] = array("x" => "aaa", "y" => "bbb");
$temp1[] = array("x" => "ccc", "y" => "ddd");
$temp1[] = array("x" => "eee", "y" => "fff");

unset($temp1[0]);

$encoded = json_encode($temp1);

echo $encoded;

它将输出

{1:{x:ccc，y:ddd}，2:{x:eee，y:fff}

如何使第二个代码与第一个代码一样工作？在我看来，这是预期的结果，因为从数组中删除和元素的行为不应影响输出编码字符串的结构。

unset将保持索引不变，因此，在使用unset后，可以使用array\u值重新计算数据：

        $temp1 = array();
        $temp1[] = array("x" => "aaa", "y" => "bbb");
        $temp1[] = array("x" => "ccc", "y" => "ddd");
        $temp1[] = array("x" => "eee", "y" => "fff");

        array_splice($temp1,0,1);

        $encoded = json_encode($temp1);
        echo $encoded;

---

数组_值正是我应该使用的！它工作得很完美，塔什克！您的代码可以工作，但数组_值是一种更通用、更好的方法。无论如何，谢谢，您的解决方案运行良好：

<?php
$temp1 = array();

$temp1[] = array("x" => "aaa", "y" => "bbb");
$temp1[] = array("x" => "ccc", "y" => "ddd");
$temp1[] = array("x" => "eee", "y" => "fff");

unset($temp1[0]);
$temp1 = array_values($temp1);
$encoded = json_encode($temp1);

echo $encoded;
// will output the expected result:[{"x":"ccc","y":"ddd"},{"x":"eee","y":"fff"}]
?>