PHP MySQL只显示空白表

你好！我在显示表中的数据时遇到问题。我已经输入了6个数据，它将显示我的$I++中有多少个基数，但它没有显示userno、fullname和udate。我真的很感激，谢谢你！这是我的密码：

table class="table table-striped table-sm">
  <thead>
    <tr>
      <th>No</th>
      <th>User No</th>
      <th>User Name</th>
      <th>Date Registered</th>
    </tr>
  </thead>
  <tbody>

    <?php
      $i=0;
      $uquery= mysqli_query($conn, "SELECT * FROM users");
      while ($uresult=mysqli_fetch_array($uquery)){

      $i++;  
    ?>
      <tr>
        <td><?php echo $i;?></td>
        <td><?php $uresult ['userno'];?></td>
        <td><?php $uresult ['fullname'];?></td>
        <td><?php $uresult ['udate'];?></td>

    <?php }; ?> 
  </tbody>
</table>

---

首先，您错过了结束，其次，您真的必须使用变量i并递增它吗？在哪里可以回显所有ID？最后，你应该在变量uresult中加上echo，希望这能对你有所帮助

<table class="table table-striped table-sm">
<thead>
<tr>
  <th>No</th>
  <th>User No</th>
  <th>User Name</th>
  <th>Date Registered</th>
</tr>
</thead>
<tbody>

<?php
  $uquery= mysqli_query($conn, "SELECT * FROM users");
  while ($uresult=mysqli_fetch_array($uquery)){
?>
  <tr>
    <td><?php echo $uresult ['id'];?></td>
    <td><?php echo $uresult ['userno'];?></td>
    <td><?php echo $uresult ['fullname'];?></td>
    <td><?php echo $uresult ['udate'];?></td>
  </tr>
<?php } ?> 
</tbody>
</table>




and also you can write it, in this way:
and echo variable `i` if you want to see the count of it.
<?php
  $uquery= "SELECT * from users";
  $viewquery = mysqli_query($con,$uquery);
  while($uresult = mysqli_fetch_assoc($viewquery))
{
?>

---

这将是您的PHP，根据您的表进行相应调整，希望这对您有所帮助

你忘记回显你的结果了

改变

<td><?php $uresult ['userno'];?></td>
<td><?php $uresult ['fullname'];?></td>
<td><?php $uresult ['udate'];?></td>

到

或

<td><?php $uresult ['userno'];?></td>
<td><?php $uresult ['fullname'];?></td>
<td><?php $uresult ['udate'];?></td>

<td><?php echo $uresult ['userno'];?></td>
<td><?php echo $uresult ['fullname'];?></td>
<td><?php echo $uresult ['udate'];?></td>

<td><?= $uresult ['userno'];?></td>
<td><?= $uresult ['fullname'];?></td>
<td><?= $uresult ['udate'];?></td>