Php 搜索表单未显示正确的结果

我不熟悉创建搜索表单，以下是我的搜索表单代码：

<h2>Search</h2> 
 <form name="search" method="post" action="search_result2.php">
 Search for: <input type="text" name="find" /> in 
 <Select NAME="field">
 <Option VALUE="testA">A</option>
 <Option VALUE="testB">B</option>
 <Option VALUE="testC">C</option>
 <Option VALUE="testD">D</option>
 </Select>
 <input type="hidden" name="searching" value="yes" />
 <input type="submit" name="search" value="Search" />
 </form>

---

不要使用

确实要使用
试试
$find=strtoupper（$\u POST['find']）
并使用
$\u POST
superglobal对其他两个执行相同的操作。仍然会得到相同的结果…如果短开放标记未“打开”，则更改
在第26行之前的最后一行代码中缺少分号。它应该是：
$field=trim（$\u POST['field']）是的…我想你是对的，已经修好了…在我发布那个问题后也看到了…哈哈…谢谢你的帮助：）我不再得到初始错误，但我得到了这个：
解析错误：语法错误，意外的“$data”（T_变量）在第26行的C:\xampp\htdocs\Templates\search\u result2.php中，第26行引用了以下内容：
$data=mysql\u查询（“从testtable中选择*，上面（$field）如“%$find%”）您在第26行之前的最后一行代码中遗漏了分号。它应该是：
$field=trim（$\u POST['field']）
<?php
 //This is only displayed if they have submitted the form 
if (isset($_POST['searching']) && $_POST['searching'] == "yes") 
{ 
echo "<h2>Results</h2><p>"; 
//If they did not enter a search term we give them an error 
if (empty($_POST['find'])) 
{ 
echo "<p>You forgot to enter a search term"; 
exit; 
} 
 
 // Otherwise we connect to our Database 
 mysql_connect("host", "username", "passw") or die(mysql_error()); 
 mysql_select_db("testdb") or die(mysql_error()); 
 
 // We preform a bit of filtering 
 $find = strtoupper($_POST['find']); 
 $find = strip_tags($_POST['find']); 
 $find = trim ($_POST['find']); 
 $field = trim ($_POST['field'])
 
 //Now we search for our search term, in the field the user specified 
 $data = mysql_query("SELECT * FROM testtable WHERE upper($field) LIKE'%$find%'"); 
 
 
 //And we display the results 
 while($result = mysql_fetch_array( $data )) 
 { 
 echo $result['testA']; 
 echo " "; 
 echo $result['testB']; 
 echo "<br>"; 
 echo $result['testC']; 
 echo "<br>"; 
 echo $result['testD']; 
 echo "<br>"; 
 echo "<br>"; 
 } 
 
 //This counts the number or results - and if there wasn't any it gives them a little message explaining that 
 $anymatches=mysql_num_rows($data); 
 if ($anymatches == 0) 
 { 
 echo "Sorry, but we can not find an entry to match your query<br><br>"; 
 } 
 
 //And we remind them what they searched for 
 echo "<b>Searched For:</b> " .$find; 
 } 
 ?>

Results:

    "; //If they did not enter a search term we give them an error if ($find == "") { echo "
    
    You forgot to enter a search term";
    exit;
    } // Otherwise we connect to our Database
    mysql_connect("host", "username", "passw") or die(mysql_error());
    mysql_select_db("testdb") or die(mysql_error());
    // We preform a bit of filtering $find = strtoupper($find);
    $find = strip_tags($find);
    $find = trim ($find);
    //Now we search for our search term, in the field the user specified
    $data = mysql_query("SELECT * FROM testtable WHERE upper($field) LIKE'%$find%'");
    //And we display the results
    while($result = mysql_fetch_array( $data )) {
        echo $result['testA'];
        echo " ";
        echo $result['testB'];
        echo "    ";
        echo $result['testC'];
        echo "    ";
        echo $result['testD'];
        echo "    ";
        echo "  ";
    } //This counts the number or results - and if there wasn't any it gives them a little message explaining that $anymatches=mysql_num_rows($data); if ($anymatches == 0) { echo "Sorry, but we can not find an entry to match your query
    
    "; } //And we remind them what they searched for echo "Searched For: " .$find; } ?>

if (isset($_POST['searching']) && $_POST['searching'] == "yes") 
{ 
echo "<h2>Results</h2><p>"; 

//If they did not enter a search term we give them an error 
if (empty($_POST['find'])) 
{ 
echo "<p>You forgot to enter a search term"; 
exit; 
}