Php 替换MySQL中的空值
使用此项时如何查找和替换空行Php 替换MySQL中的空值,php,mysql,Php,Mysql,使用此项时如何查找和替换空行 $Qemaster="select * from emaster where `branch`='$bid' and `department`='$did' and `status`!='L'"; $Remaster=mysql_query($Qemaster); while($Rowemaster=mysql_fetch_array($Remaster)){ $empcode=$Rowemaster[id]; $name=$Rowemaster[n
$Qemaster="select * from emaster where `branch`='$bid' and `department`='$did' and `status`!='L'";
$Remaster=mysql_query($Qemaster);
while($Rowemaster=mysql_fetch_array($Remaster)){
$empcode=$Rowemaster[id];
$name=$Rowemaster[name];
$Tleave=0;
echo "<tr>";
echo "<td rowspan='2'>".$name."</td>";
echo "<td>Leave</td>";
$Qlp="select * from lpsummary where ((`month` IN(04,05,06,07,08,09,10,11,12) and `year`='$year') or (`month` IN (01,02,03) and `year`='$Nyear')) and `empcode`='$empcode'";
$Rlp=mysql_query($Qlp);
$RRlp=mysql_num_rows($Rlp);
while($Rowlp=mysql_fetch_array($Rlp)){
$leave=$Rowlp['leave'];
$Tleave=$Tleave+$leave;
if($leave==NULL){
$Eleave='-';
}
else{
$Eleave=$leave;
}
echo "<td>".$Eleave."</td>";
}
echo "<td><font color='red'>".$Tleave."</font></td>";
echo "<td><font color='green'>".substr(($Tleave/$RRlp),0,4)."</font></td>";
echo "<tr><td>Percentage</td>";
}
$Qemaster=“从emaster中选择*,其中“分支机构”='$bid'和“部门”='$did'以及“状态”!='L';
$Remaster=mysql\u查询($Qemaster);
while($Rowemaster=mysql\u fetch\u数组($Remaster)){
$empcode=$Rowemaster[id];
$name=$Rowemaster[name];
$Tleave=0;
回声“;
回显“$name.”;
呼应“离开”;
$Qlp=“从lpsummary中选择*,其中((04,05,06,07,08,09,10,11,12)中的'month'和'year'='year')或((01,02,03)中的'month'和'year'='Nyear')和'empcode'='empcode';
$Rlp=mysql\u查询($Qlp);
$RRlp=mysql\u num\u行($Rlp);
而($Rowlp=mysql_fetch_数组($Rlp)){
$leave=$Rowlp['leave'];
$Tleave=$Tleave+$LEVE;
如果($leave==NULL){
$Eleave='-';
}
否则{
$Eleave=$leave;
}
回声“$Eleave.”;
}
回声“$Tleave.”;
回显“.substr($Tleave/$RRlp),0,4”);
回声“百分比”;
}
如果有一个空行。。。我想把它替换成-而不是回声“$Eleave” 实际上,您可以通过查询直接执行此操作,这样您的php代码中就不会有任何
IF-ELSE
条件
另外,要养成指定列名的习惯,而不是使用*
SELECT colnames,..., COALESCE(`leave`, '-') `Leave`
FROM lpsummary
WHERE .....
更新1
SELECT COALESCE(l.leave, '-') AS `LEAVE`
FROM lpsummary l
WHERE (
(month IN(04,05,06,07,08,09,10,11,12) and year='$year') or
(month IN (01,02,03) and year='$Nyear')
) and empcode='$empcode'
作为旁注,如果变量的值来自外部,则查询易受攻击。请看下面的文章,了解如何预防它。通过使用
PreparedStatements
可以避免在值周围使用单引号
休假
,”-”),从lpsummary中(月
在(04,05,06,07,08,09,10,11,12)和年
='$year')或(月
在(01,02,03)和年
='$Nyear'))和empcode
='$empcode;但获取错误作为警告:mysql\u fetch\u array():提供的参数在资源中不是有效的mysql结果