Php 多维数组上的Group by

我担心我想做的事情是不可能的，但我希望你能帮助我找到解决这个问题的好方法

我得到了以下PHP数组：

Array ( 
    [0] => Array ( [article] => 10.499-1 [operation] => KN_KABEL [date] => 31-05-2013 [hours] => 0 [quantity] => 1 ) 
    [1] => Array ( [article] => 10.499-1 [operation] => LAS_LABEL [date] => 31-05-2013 [hours] => 0 [quantity] => 1 ) 
    [2] => Array ( [article] => 10.499-1 [operation] => ASS_HARNES [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [3] => Array ( [article] => 10.499-1 [operation] => CONTROLE [date] => 07-06-2013 [hours] => 0 [quantity] => 1 ) 
    [4] => Array ( [article] => 24.030 [operation] => LAS_LABEL [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [5] => Array ( [article] => 24.030 [operation] => ZAGEN-RAIL [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [6] => Array ( [article] => 24.030 [operation] => KN_KABEL [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [7] => Array ( [article] => 24.030 [operation] => ASS_RAIL [date] => 05-06-2013 [hours] => 0 [quantity] => 1 ) 
    [8] => Array ( [article] => 791 070-6/GS/P [operation] => GS_UNIT [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [9] => Array ( [article] => 791 070-6/GS/P [operation] => PR_UNIT [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [10] => Array ( [article] => 791 070-6/GS/P [operation] => LAS_LABEL [date] => 04-06-2013 [hours] => 0 [quantity] => 1 ) 
    [11] => Array ( [article] => ESS-0834E/LE-CD200 [operation] => MAGAZIJN [date] => 10-06-2013 [hours] => 0 [quantity] => 1 ) 
    [12] => Array ( [article] => ESS-0834E/LE-CD200 [operation] => PR_UNIT [date] => 11-06-2013 [hours] => 0 [quantity] => 1 ) 
    [13] => Array ( [article] => ESS-0834E/LE-CD200 [operation] => LAB_PLAKKE [date] => 11-06-2013 [hours] => 0 [quantity] => 1 )
)  

我试图做的是计算每个日期（关键“数据”）的小时数总和（在本例中，它们都是0，但我仍然希望这样做，因为这将在未来发生变化）。非常实用的方法是执行类似sql的查询，如

选择按日期分组的总和（小时数）

，但不幸的是，这不是sql

是否有一种方法可以按特定键（在本例中为“日期”）对数组进行分组（和排序），或者，如果没有，是否有其他方法可以获得我想要的结果

编辑

---

我最近添加了一个关键的“部门”，它应该按to分组。因此，我不仅要计算“小时”的总和，还要计算“数量”

只需为此创建简单的foreach即可

$arr = array();

$sums = array();
foreach($arr as $k=>$v)
{
     if(!isset($sums[$v['date']][$v['department']]['hours'])) $sums[$v['date']][$v['department']]['hours'] = 0;
     if(!isset($sums[$v['date']][$v['department']]['quantity'])) $sums[$v['date']][$v['department']]['quantity'] = 0;
     $sums[$v['date']][$v['department']]['hours'] += $v['hours'];
     $sums[$v['date']][$v['department']]['quantity'] += $v['quantity'];
}
print_r($sums);

它将创建数组

$sum

，其中键是日期。如果值不存在，则将小时值添加到0，否则如果值存在，则将添加到现有值

编辑

---

适合OP需求。

这对我来说非常有用，谢谢！2个问题？我在数组中添加了一个关键的“部门”。也可以“分组”2列。第二：我也想数一数关键的“数量”。是否可以在相同的代码中执行此操作？很抱歉在我的问题中没有注意到这一点。我将编辑我的问题和课程的附加要求，这是可能的

$sums[$v['date']][$v['department']]]

小的变化和它的工作：）数量可以以同样的方式计算；）$sums[$v['date'][$v['department']]数组的值也可以是数组，您可以在其中输入小时数和数量并求和。您从代码中删除了“in_array（）”部分，这是您的意图还是您忘记了它？因为现在我有很多未定义的索引错误