Php 漂亮的URL访问

我有下面的网址，我想美化。谢谢你的帮助

来自

到

我在下面尝试过，但得到内部服务器错误

# external redirect from actual URL to pretty one (WEB)
RewriteCond %{THE_REQUEST} \s/+search-menu(?:\.php)?\?r_id=([^\s&]+)&name=([^\s&]+) [NC]
RewriteRule ^ /search-menu/%1/%2? [R=302,L,NE]

# internal forward from pretty URL to actual one (WEB)
RewriteRule ^search-menu/([\w-]+)/([\w-]+)/?$ search-menu.php?r_id=$1&name=%2 [L,QSA,NC]

仅供参考：以下规则删除.php扩展站点范围

# To externally redirect /dir/foo.php to /dir/foo
RewriteCond %{THE_REQUEST} ^[A-Z]{3,}\s([^.]+)\.php [NC]
RewriteRule ^ %1 [R=302,L]

## To internally redirect /dir/foo to /dir/foo.php
RewriteCond %{REQUEST_FILENAME}.php -f [NC]
RewriteRule ^(.+?)/?$ $1.php [L]

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找到适合您的内容-向导将帮助您完善URL

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将此行添加到.htaccess文件中。它将接受变量并使其变得漂亮：

RewriteEngine On
RewriteRule ^([^/]*)/([^/]*)\.html$ /search-menu?r_id=$1&name=$2 [L]

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请记住，这是基本的，您需要将其修改为您的地址，但这只是为了让您了解需要做什么。

在您的htaccess中尝试以下操作：

RewriteEngine on

RewriteCond %{THE_REQUEST} /search-menu\?r_id=([^&]+)&name=([^\s]+) [NC]
RewriteRule ^ %1/%2? [NC,L,R]
RewriteCond %{REQUEST_FILENAME} !-d
 RewriteCond %{REQUEST_FILENAME} !-f
 RewriteRule ^search-menu/([^/]+)/([^/]+)/?$ search-menu.php?r_id=$1&name=$2 [NC,L]

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RewriteRule^（.*）？Page=$1&Section=$2-正则表达式可能不是100%正确，它将为您提供一个idea@moh.ABK你的.htaccess文件这让我进入页面，但没有加载任何内容，例如css、js等。你需要在网页的中间添加一个和，以更正标题的uri基，以便js和css可以工作。阅读

RewriteEngine On
RewriteRule ^([^/]*)/([^/]*)\.html$ /search-menu?r_id=$1&name=$2 [L]

RewriteEngine on

RewriteCond %{THE_REQUEST} /search-menu\?r_id=([^&]+)&name=([^\s]+) [NC]
RewriteRule ^ %1/%2? [NC,L,R]
RewriteCond %{REQUEST_FILENAME} !-d
 RewriteCond %{REQUEST_FILENAME} !-f
 RewriteRule ^search-menu/([^/]+)/([^/]+)/?$ search-menu.php?r_id=$1&name=$2 [NC,L]