Php Codeigniter动态数据库连接

Php Codeigniter动态数据库连接,php,mysql,database,codeigniter,dynamic,Php,Mysql,Database,Codeigniter,Dynamic,我是php/OOP的初学者,对动态更改数据库连接有疑问 下面是my main.php的外观: <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class Main extends CI_Controller { function __construct() { parent::__construct(); /* Standard Libraries of cod

我是php/OOP的初学者,对动态更改数据库连接有疑问

下面是my main.php的外观:

<?php  if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class Main extends CI_Controller {


function __construct()
{

    parent::__construct();

    /* Standard Libraries of codeigniter are required */
    $this->load->database($connectdb);
    $this->load->helper('url');
    $this->load->library('grocery_CRUD');
}

public function index()
{


            if ($_POST["username"] == "root")
                    {
                            $connectdb="default";
                    }


                    if ($_POST["username"] == "user1")
                    {
                            $connectdb="default1";
                    }

            if ($_POST["username"] == "user2")
                    {
                            $connectdb="default2";
                    }


    $connect = @mysql_connect("localhost", $_POST["username"], $_POST["password"]);//won't display the warning if any.
    if (!$connect)
    {
            echo 'Server error. Please try again sometime. CON';
    }else{
            print("<a href=\"http://v-admindb/ci/index.php/main/employees?username=".$_POST["username"]."\">Employees</a>");
            echo "<br>";
            print("<a href=\"http://v-admindb/ci/index.php/main/visitors?username=".$_POST["username"]."\">Visitors</a>");
    }//Just an example to ensure that we get into the function
// LOAD LIBRARIES
}

public function employees()
{
    $this->grocery_crud->set_table('employees');
    $output = $this->grocery_crud->render();
    $this->_example_output($output);
}

public function visitors()
{
    $this->grocery_crud->set_table('visitors');
    $output = $this->grocery_crud->render();
    $this->_example_output($output);
}


function _example_output($output = null)

{
    $this->load->view('our_template.php',$output);
}
}
当我尝试登录时,我可以看到以下错误:

遇到一个PHP错误

严重性:通知

消息:未定义变量:connectdb

文件名:controllers/main.php

行号:12遇到错误

您尚未选择要连接的数据库类型

$this->load->database($connectdb)
更改为
default
default1
,或
default2
使其工作。如何将变量放入其中,以便连接参数根据登录用户的不同而变化

希望有人能帮忙,谢谢!
Eric

您应该在
application/config/database.php´

通常,您会设置默认数据库组,如下所示:

$db['default']['hostname'] = "localhost";
$db['default']['username'] = "root";
$db['default']['password'] = "";
$db['default']['database'] = "database_name";
$db['default']['dbdriver'] = "mysql";
$db['default']['dbprefix'] = "";
$db['default']['pconnect'] = TRUE;
$db['default']['db_debug'] = FALSE;
$db['default']['cache_on'] = FALSE;
$db['default']['cachedir'] = "";
$db['default']['char_set'] = "utf8";
$db['default']['dbcollat'] = "utf8_general_ci";
$db['default']['swap_pre'] = "";
$db['default']['autoinit'] = TRUE;
$db['default']['stricton'] = FALSE;
请注意,登录信息和设置在名为
$db['default']
的数组中提供

然后,您可以在一个新数组中添加另一个数据库——我们称之为“anotherdb”

$db['anotherdb']['hostname'] = "localhost";
$db['anotherdb']['username'] = "root";
$db['anotherdb']['password'] = "";
$db['anotherdb']['database'] = "another_database_name";
$db['anotherdb']['dbdriver'] = "mysql";
$db['anotherdb']['dbprefix'] = "";
$db['anotherdb']['pconnect'] = TRUE;
$db['anotherdb']['db_debug'] = FALSE;
$db['anotherdb']['cache_on'] = FALSE;
$db['anotherdb']['cachedir'] = "";
$db['anotherdb']['char_set'] = "utf8";
$db['anotherdb']['dbcollat'] = "utf8_general_ci";
$db['anotherdb']['swap_pre'] = "";
$db['anotherdb']['autoinit'] = TRUE;
$db['anotherdb']['stricton'] = FALSE;
现在,如果您想使用第二个数据库,只需

$DB_another = $this->load->database('anotherdb', TRUE); 
然后,您将不再使用
$this->db->foo()
,而是使用
$db\u other->foo()

你可以像这样把它扩展到多个组

 $DB2 = $this->load->database('anotherdb1', TRUE); 
 $DB3 = $this->load->database('anotherdb2', TRUE); 
有关详细信息,请参见:

您应该在
application/config/database.php´

通常,您会设置默认数据库组,如下所示:

$db['default']['hostname'] = "localhost";
$db['default']['username'] = "root";
$db['default']['password'] = "";
$db['default']['database'] = "database_name";
$db['default']['dbdriver'] = "mysql";
$db['default']['dbprefix'] = "";
$db['default']['pconnect'] = TRUE;
$db['default']['db_debug'] = FALSE;
$db['default']['cache_on'] = FALSE;
$db['default']['cachedir'] = "";
$db['default']['char_set'] = "utf8";
$db['default']['dbcollat'] = "utf8_general_ci";
$db['default']['swap_pre'] = "";
$db['default']['autoinit'] = TRUE;
$db['default']['stricton'] = FALSE;
请注意,登录信息和设置在名为
$db['default']
的数组中提供

然后,您可以在一个新数组中添加另一个数据库——我们称之为“anotherdb”

$db['anotherdb']['hostname'] = "localhost";
$db['anotherdb']['username'] = "root";
$db['anotherdb']['password'] = "";
$db['anotherdb']['database'] = "another_database_name";
$db['anotherdb']['dbdriver'] = "mysql";
$db['anotherdb']['dbprefix'] = "";
$db['anotherdb']['pconnect'] = TRUE;
$db['anotherdb']['db_debug'] = FALSE;
$db['anotherdb']['cache_on'] = FALSE;
$db['anotherdb']['cachedir'] = "";
$db['anotherdb']['char_set'] = "utf8";
$db['anotherdb']['dbcollat'] = "utf8_general_ci";
$db['anotherdb']['swap_pre'] = "";
$db['anotherdb']['autoinit'] = TRUE;
$db['anotherdb']['stricton'] = FALSE;
现在,如果您想使用第二个数据库,只需

$DB_another = $this->load->database('anotherdb', TRUE); 
然后,您将不再使用
$this->db->foo()
,而是使用
$db\u other->foo()

你可以像这样把它扩展到多个组

 $DB2 = $this->load->database('anotherdb1', TRUE); 
 $DB3 = $this->load->database('anotherdb2', TRUE); 
有关详细信息,请参见:

问题是,在索引函数中设置的构造函数中加载此变量

\uu构造函数()在index()之前被激发,所以我想你应该这样做:

class Main extends CI_Controller {
private $connectdb;

function __construct()
{

    parent::__construct();

    /* Standard Libraries of codeigniter are required */
    $this->_setConnectdb();
    $this->load->database($this->connectdb);
    $this->load->helper('url');
    $this->load->library('grocery_CRUD');
}

public function _setConnectdb()
{
if ( $_POST["username"] == "root" ) {
    $this->connectdb = "default";
}

if ( $_POST["username"] == "user1" ) {
    $this->connectdb = "default1";
}

if ( $_POST["username"] == "user2" ) {
    $this->connectdb = "default2";
}
问题是,在索引函数中设置的构造函数中加载此变量

\uu构造函数()在index()之前被激发,所以我想你应该这样做:

class Main extends CI_Controller {
private $connectdb;

function __construct()
{

    parent::__construct();

    /* Standard Libraries of codeigniter are required */
    $this->_setConnectdb();
    $this->load->database($this->connectdb);
    $this->load->helper('url');
    $this->load->library('grocery_CRUD');
}

public function _setConnectdb()
{
if ( $_POST["username"] == "root" ) {
    $this->connectdb = "default";
}

if ( $_POST["username"] == "user1" ) {
    $this->connectdb = "default1";
}

if ( $_POST["username"] == "user2" ) {
    $this->connectdb = "default2";
}

我只有一个数据库和多个表。似乎上面的内容只适用于不同的数据库。有没有办法在main.php中动态更改数据库连接?我只有一个数据库和多个表。似乎上面的内容只适用于不同的数据库。是否有一种方法可以动态更改main.php中的数据库连接?如果要使用codeigniter,请先阅读一些手册…如果要使用codeigniter,请先阅读一些手册。。。