Php 数组组合保持索引

我试图将四个数组合并为一个，同时保留整个数组的索引号

示例阵列：

$codes = array('US', 'GB', 'AE');
$names = array('United States', 'United Kingdom', 'United Arab Emirates');
$population = array('307,212,123', '61,113,205', '4,798,491');
$area = array('9,826,675', '243,610', '83,600');

我希望有一个可以像这样使用的函数：

如果可能，还可以支持更多阵列，如第五阵列等

通缉结果:

    [country] => Array
      (
        [0] => Array
          (
            [0] => US
            [1] => United States
            [2] => 307,212,123
            [3] => 9,826,675
          )
        [1] => Array
          (
            [0] => GB
            [1] => United Kingdom
            [2] => 61,113,205
            [3] => 243,610
          )
        [2] => Array
          (
            [0] => AE
            [1] => United Arab Emirates
            [2] => 4,798,491
            [3] => 83,600
          )
      )

---

非常感谢您提供的所有帮助^ ^ ^

通常，数组ID的重置是由array ^ merge PHP函数引起的，而不是使用该函数尝试简单地“添加”数组以形成合并的数组，下面的示例应该有助于了解发生了什么

因此，我们从两个小而简单的数组开始，其索引设置为默认值0以外的值

$array1 = array(1 => 'one');
$array2 = array(3 => 'three');

使用“普通”数组\u merge可以执行类似的操作，因为您可以看到两个数组ID都已重置为0和1，其中在合并之前分别为1和3

$mergedArray = array_merge($array1, $array2);
// $mergedArray = array(0 => 'one', 1 => 'three');

但是，将两个数组添加到一起时，索引ID将保持不变：

$mergedArray = $array1 + $array2; // will keep the index ID's intact
// $mergedArray = array(1 => 'one', 3 => 'three');

---

我用这个定制的功能得到了这个。感谢Trey提供的原始函数，您可以使用此函数添加任意数量的数组

职能1：

function arrayMerge() {
    $args = func_get_args();
    $idx1 = range(1, count($args[1]));
    $idx2 = range(1, count($args[2]));
    foreach($args as $key => $array) {
        $vkey = array_shift($idx2);
        foreach($array as $akey => $val) {
            $result[$idx1[$akey]][$vkey] = $val;
        } #foreach
    } #foreach
    return $result;
} #arrayMerge

使用的示例阵列：

$codes = array('US', 'GB', 'AE');
$names = array('United States', 'United Kingdom', 'United Arab Emirates');
$population = array('307,212,123', '61,113,205', '4,798,491');
$area = array('9,826,675', '243,610', '83,600');

$codes = array('US', 'GB', 'AE');
$names = array('United States', 'United Kingdom', 'United Arab Emirates');
$population = array('307,212,123', '61,113,205', '4,798,491');
$area = array('9,826,675', '243,610', '83,600');
$keys = array('code', 'name', 'popu', 'area');

功能使用：

print_r( arrayMerge($codes, $names, $population, $area) );

print_r( arrayMerge2($keys, $codes, $names, $population, $area) );

我添加了两个自动数字索引，从0的1个instad开始

阵列输出示例：

Array
  (
    [1] => Array
      (
        [1] => US
        [2] => United States
        [3] => 307,212,123
        [4] => 9,826,675
      )
    [2] => Array
      (
        [1] => GB
        [2] => United Kingdom
        [3] => 61,113,205
        [4] => 243,610
      )
    [3] => Array
      (
        [1] => AE
        [2] => United Arab Emirates
        [3] => 4,798,491
        [4] => 83,600
      )
  )

Array
  (
    [1] => Array
      (
        [code] => US
        [name] => United States
        [popu] => 307,212,123
        [area] => 9,826,675
      )
    [2] => Array
      (
        [code] => GB
        [name] => United Kingdom
        [popu] => 61,113,205
        [area] => 243,610
      )
    [3] => Array
      (
        [code] => AE
        [name] => United Arab Emirates
        [popu] => 4,798,491
        [area] => 83,600
      )
  )

这里还有一个使用自定义子键的方法，在这个方法中，我添加了一个自动命名索引，并从1开始，而不是从0开始

职能2：

function arrayMerge2() {
    $args = func_get_args();
    $idx = range(1, count($args[1]));
    $keys = array_shift($args);
    foreach($args as $key => $array) {
        $vkey = array_shift($keys);
        foreach($array as $akey => $val) {
            $result[$idx[$akey]][$vkey] = $val;
        } #foreach
    } #foreach
    return $result;
} #arrayMerge2

使用的示例阵列：

$codes = array('US', 'GB', 'AE');
$names = array('United States', 'United Kingdom', 'United Arab Emirates');
$population = array('307,212,123', '61,113,205', '4,798,491');
$area = array('9,826,675', '243,610', '83,600');

$codes = array('US', 'GB', 'AE');
$names = array('United States', 'United Kingdom', 'United Arab Emirates');
$population = array('307,212,123', '61,113,205', '4,798,491');
$area = array('9,826,675', '243,610', '83,600');
$keys = array('code', 'name', 'popu', 'area');

功能使用：

print_r( arrayMerge($codes, $names, $population, $area) );

print_r( arrayMerge2($keys, $codes, $names, $population, $area) );

阵列输出示例：

Array
  (
    [1] => Array
      (
        [1] => US
        [2] => United States
        [3] => 307,212,123
        [4] => 9,826,675
      )
    [2] => Array
      (
        [1] => GB
        [2] => United Kingdom
        [3] => 61,113,205
        [4] => 243,610
      )
    [3] => Array
      (
        [1] => AE
        [2] => United Arab Emirates
        [3] => 4,798,491
        [4] => 83,600
      )
  )

Array
  (
    [1] => Array
      (
        [code] => US
        [name] => United States
        [popu] => 307,212,123
        [area] => 9,826,675
      )
    [2] => Array
      (
        [code] => GB
        [name] => United Kingdom
        [popu] => 61,113,205
        [area] => 243,610
      )
    [3] => Array
      (
        [code] => AE
        [name] => United Arab Emirates
        [popu] => 4,798,491
        [area] => 83,600
      )
  )

哦，是的，这个函数还支持数组中的空值：-

---

我希望这能帮助其他需要simular阵列配置的人。

这将为您提供所需的精确输出。希望它对你有用

<?php
$codes = array('US', 'GB', 'AE');
$names = array('United States', 'United Kingdom', 'United Arab Emirates');
$population = array('307,212,123', '61,113,205', '4,798,491');
$area = array('9,826,675', '243,610', '83,600');

$country = array();
$size= sizeof($codes); //This will work only if all array size are same.

for($i=0;$i<$size;$i++)
{
    $country[$i][]=$codes[$i];
    $country[$i][]=$names[$i];
    $country[$i][]=$population[$i];
    $country[$i][]=$area[$i];
}
echo "<pre>";
print_r($country);

---

你已经试过什么了吗？具体到哪里去了？源数组是什么样的？请看上面，我编辑了这篇文章。这不起作用，因为它没有像示例中所示的那样组合数组。我已经试过这种方法了。