Php 删除第二对括号的正则表达式（仅在可用时）

我有这样的想法：

$arr[] = 'Seto Hakashima'
$arr[] = 'Anna (segment "Yvan Attal") (as Robin Wright Penn)'
$arr[] = 'Sara (segment "Yvan Attal")'

我需要删除第二对括号（仅当存在第二对括号时），并得到以下结果：

$arr[] = 'Seto Hakashima'
$arr[] = 'Anna (segment "Yvan Attal")'
$arr[] = 'Sara (segment "Yvan Attal")'

谢谢

试试看

preg_replace('/^([^(]+(?:\([^)]+\))?).*/','$1', $item);

很少解释

^          - start of the string
[^(]+      - match characters before first bracket
\([^)]+\)  - match first bracket
(?: ... )? - optional
.*         - eat the rest
$1         - replace with match string

或者干脆去掉最后一部分

preg_replace('/(?<=\))\s*\(.*$/','', $item);

(?<=\))    - if there is ) before pattern
(\s*\(.*$  - remove everything after `(` and also zero or more whitespaces before last bracket.

preg_replace（'/（？此功能：

<?php
$arr[] = 'Seto Hakashima';
$arr[] = 'Anna (segment "Yvan Attal") (as Robin Wright Penn)';
$arr[] = 'Sara (segment "Yvan Attal")';
$arr[] = 'Anna (segment "Yvan Attal") (as Robin Wright Penn) BONUS text after second group';

foreach ($arr as $item) {
    print preg_replace('/(\([^\)]*\)[^\(]+)\([^\)]*\)\s*/','$1',$item) . "\n";
}

是的，括号内的括号不支持这一点。