Php 如何将查询mysql转换为laravel查询

Hai我在mysql中所有的原始查询都需要翻译成laravel 5.4查询生成器：

SELECT MONTH(calendar.datefield) AS Bulan, calendar.datefield AS Tanggal, IFNULL(SUM(dbk.jumlah),0) AS Jumlah 
FROM detail_brg_keluar AS dbk 
INNER JOIN penjualan AS pen ON pen.id = dbk.id_brg_keluar 
RIGHT JOIN calendar ON (DATE(pen.tgl_keluar) = calendar.datefield)
WHERE 
(calendar.datefield BETWEEN 
 (SELECT MIN(DATE(tgl_keluar)) FROM penjualan AS p
    INNER JOIN detail_brg_keluar AS detail ON p.id = detail.id_brg_keluar 
    WHERE detail.id_produk = 818002) 
 AND 
 (SELECT MAX(DATE(tgl_keluar)) FROM penjualan AS pe
    INNER JOIN detail_brg_keluar AS det ON pe.id = det.id_brg_keluar
    WHERE det.id_produk = 818002))
AND (dbk.id_produk = 818002 OR dbk.id_produk IS NULL)
GROUP BY MONTH(calendar.datefield)
ORDER BY calendar.datefield ASC

这是我的laravel代码，代码错误-_-

$proT = DB::table('detail_brg_keluar AS dbk')
    ->select( DB::raw('MONTH(calendar.datefield) AS Bulan, calendar.datefield AS Tanggal, IFNULL(SUM(dbk.jumlah),0) AS Jumlah '))
    ->join('penjualan AS pen', 'pen.id', '=', 'dbk.id_brg_keluar')
    ->join('calendar', DB::raw('DATE(pen.tgl_keluar)'), '=', 'calendar.datefield')
    ->whereBetween('calendar.datefield', [$from[0]->tanggalAwal, $to[0]->tanggalAkhir])
    ->where(DB::raw('dbk.id_produk = 818002 OR dbk.id_produk IS NULL'))
    ->groupBy(DB::raw('MONTH(calendar.datefield)'))
    ->orderBy(DB::raw('calendar.datefield', 'ASC'))
    ->get();

代码从和到：

$from = DB::table('penjualan AS p')
    ->select(DB::raw('MIN(DATE(tgl_keluar)) AS tanggalAwal'))
    ->join('detail_brg_keluar AS detail', 'p.id', '=', 'detail.id_brg_keluar')
    ->where('detail.id_produk', $id)
    ->get();

$to = DB::table('penjualan AS p')
    ->select(DB::raw('MAX(DATE(tgl_keluar)) AS tanggalAkhir'))
    ->join('detail_brg_keluar AS detail', 'p.id', '=', 'detail.id_brg_keluar')
    ->where('detail.id_produk', $id)
    ->get();

我不知道了

Thx all

使用此选项：

$from = DB::table('penjualan AS p')
    ->select(DB::raw('MIN(DATE(tgl_keluar)) AS tanggalAwal'))
    ->join('detail_brg_keluar AS detail', 'p.id', '=', 'detail.id_brg_keluar')
    ->where('detail.id_produk', $id);
$to = DB::table('penjualan AS p')
    ->select(DB::raw('MAX(DATE(tgl_keluar)) AS tanggalAkhir'))
    ->join('detail_brg_keluar AS detail', 'p.id', '=', 'detail.id_brg_keluar')
    ->where('detail.id_produk', $id);
$proT = DB::table('detail_brg_keluar AS dbk')
    ->select( DB::raw('MONTH(calendar.datefield) AS Bulan, calendar.datefield AS Tanggal, IFNULL(SUM(dbk.jumlah),0) AS Jumlah '))
    ->join('penjualan AS pen', 'pen.id', '=', 'dbk.id_brg_keluar')
    ->rightJoin('calendar', DB::raw('DATE(pen.tgl_keluar)'), '=', 'calendar.datefield')
    ->whereRaw('calendar.datefield BETWEEN ('.$from->toSql().') AND ('.$to->toSql().')', [$id, $id])
    ->where(function($query) {
        $query->where('dbk.id_produk', 818002)->orWhereNull('dbk.id_produk');
    })
    ->groupBy(DB::raw('MONTH(calendar.datefield)'))
    ->orderBy('calendar.datefield', 'ASC')
    ->get();

• 不要执行

  $from

  和

  $to

  ，使用生成的SQL
• 我将

  ->join（'calendar'）

  替换为

  ->rightJoin（'calendar'）

• 我用嵌套约束替换了

  where（DB:：raw（））

• orderBy（）

  不需要原始表达式

---

很抱歉，此代码错误：“SQLSTATE[42000]：语法错误或访问冲突：1055'dbolshop.calendar.datefield'不在GROUP BY中（SQL:selectI假设您只在phpMyAdmin？中测试了原始查询，而没有在Laravel中测试（

DB:：select（$SQL）；

）？谢谢你的解决方案，查询只需稍加修改就可以了是的，我只是在phpMyAdmin中测试查询！！因为我不知道在laravel中测试查询