Php Zend Framework 2 FormSubmit调用控制器操作
如何将“提交”按钮连接到控制器操作,以便当我按下“提交”按钮时,控制器将触发特定操作 MyController:Php Zend Framework 2 FormSubmit调用控制器操作,php,html,zend-framework2,Php,Html,Zend Framework2,如何将“提交”按钮连接到控制器操作,以便当我按下“提交”按钮时,控制器将触发特定操作 MyController: class MyController extends AbstractActionController { public function viewAction() { $form = new MyForm(); $viewModel = new ViewModel(array('form' => $form));
class MyController extends AbstractActionController
{
public function viewAction()
{
$form = new MyForm();
$viewModel = new ViewModel(array('form' => $form));
$viewModel->setTemplate('myForm');
return $viewModel;
}
public function submitAction()
{
// want to trigger this
}
}
我的表格:
class MyForm extends Form
{
public function __construct()
{
parent::__construct('SubmitForm');
$this->setAttribute('method', 'post');
$this->add(array( 'name' => 'submit',
'type' => 'Zend\Form\Element\Submit',
'attributes' => array('type' => 'submit',
'value' => 'Submit',
'id' => 'submitButton'),
));
}
}
myForm.phtml:
<?php
$form = $this->form;
$form->prepare();
echo $this->form()->openTag($form);
echo $this->formSubmit($form->get('submit')); // I want pressing this element should route to MyController::submitAction...
echo $this->form()->closeTag();
?>
您可以使用:
$form->setAttribute('action', $url);
您可以使用url帮助程序获取$url
:
- 在视图中-
$this->url('my-route')代码>
- 在控制器中-
$this->url()->fromRoute('my-route')代码>