Php 易于修改以显示图像而不是url
如何显示图像而不是urlPhp 易于修改以显示图像而不是url,php,Php,如何显示图像而不是url echo "<b>Image: </b> http://graph.facebook.com/" . $posts['from']['id'] ."/picture?type=large</br>"; echo”图像:http://graph.facebook.com/" . $posts['from']['id']。“/picture?type=large”; 试试: echo“图像:”; 只需将设置为您的url: echo "&
echo "<b>Image: </b> http://graph.facebook.com/" . $posts['from']['id'] ."/picture?type=large</br>";
echo”图像:http://graph.facebook.com/" . $posts['from']['id']。“/picture?type=large”;
试试:
echo“图像:”;
只需将设置为您的url:
echo "<b>Image: </b> <img src='http://graph.facebook.com/"
. $posts['from']['id'] ."/picture?type=large'></br>";
echo“图像:”;
这将生成正确的标记。echo'Image:
;
echo '<b>Image: </b> <img src="http://graph.facebook.com/' . $posts['from']['id'] . '/picture?type=large" /><br />';
或者,在不使用串联的情况下:
<b>Image: </b> <img src="http://graph.facebook.com/<?php echo $posts['from']['id']; ?>/picture?type=large" /><br />
<b>Image: </b> <img src="http://graph.facebook.com/<?=$posts['from']['id']?>/picture?type=large" /><br />
图像:/picture?type=large”/>
或使用短标记:
图像:/picture?type=large”/>
<b>Image: </b> <img src="http://graph.facebook.com/<?php echo $posts['from']['id']; ?>/picture?type=large" /><br />
<b>Image: </b> <img src="http://graph.facebook.com/<?=$posts['from']['id']?>/picture?type=large" /><br />