Php 验证加拿大邮政编码Regex
我有一个用JavaScript编写的脚本,可以使用Regex验证加拿大邮政编码,但它似乎不起作用。以下是脚本: 如果声明:Php 验证加拿大邮政编码Regex,php,javascript,mysql,regex,Php,Javascript,Mysql,Regex,我有一个用JavaScript编写的脚本,可以使用Regex验证加拿大邮政编码,但它似乎不起作用。以下是脚本: 如果声明: if (myform.zip.value == "" || myform.zip.value == null || myform.zip.value == "Postal Code" || myform.zip.value.length < 12 ) { alert("Please fill in field Postal Code. You should o
if (myform.zip.value == "" || myform.zip.value == null || myform.zip.value == "Postal Code" || myform.zip.value.length < 12 ) {
alert("Please fill in field Postal Code. You should only enter 7 characters");
myform.zip.focus();
return false;
}
正则表达式方法可以验证,但不足以保证邮政编码实际存在 例如:
A9A 0A0
看起来像一个有效的加拿大邮政编码,但正向分拣区A9A
您确定不想对官方邮政编码列表进行某种查找吗?第一个错误是初始if语句中的最后一个条件
myform.zip.value.length<12
应始终为真,因此这部分代码将始终提示消息“请填写字段邮政编码。您只需输入7个字符”
,然后将焦点放回zip
字段。由于有效邮政编码最多有7个字符,因此应将其更改为myform.zip.value.length>7
更正后,您在注释中提供的邮政编码T2X 1V4
将生效。但是,可以简化您使用的正则表达式(注释中也提到了这一点)。您可以删除{1}
的所有实例,因为它们是冗余的。您可能还想在空格后面加一个?
而不是*
。?
表示前面的字符或表达式可以出现0或1次,而*
表示它可以出现0或更多次。我想你的邮政编码最多只需要一个空格
以下是我测试此功能的完整工作代码:
<!doctype html>
<html>
<head>
<title>JavaScript Regex Tester</title>
<meta charset="utf-8">
<script>
function validate(myform) {
if (myform.zip.value == "" || myform.zip.value == null || myform.zip.value == "Postal Code" || myform.zip.value.length > 7 ) {
alert("Please fill in field Postal Code. You should only enter 7 characters");
myform.zip.focus();
return false;
}
return okNumber(myform);
}
function okNumber(myform) {
var regex = /^[ABCEGHJKLMNPRSTVXY]\d[A-Z] *\d[A-Z]\d$/;
if (regex.test(myform.zip.value) == false) {
alert("Input Valid Postal Code");
myform.zip.focus();
return false;
}
return true;
}
</script>
</head>
<body>
<form action="#" name="myform" method="post">
<input type="text" name="zip" value="Postal Code" />
<input type="button" value="Submit" onclick="validate(document.myform);"/>
</form>
</body>
</html>
JavaScript正则表达式测试器
函数验证(myform){
如果(myform.zip.value==“”| | myform.zip.value==null | | | myform.zip.value==“邮政编码”| | myform.zip.value.length>7){
警告(“请填写字段邮政编码。您只能输入7个字符”);
myform.zip.focus();
返回false;
}
返回单号(myform);
}
函数编号(myform){
var regex=/^[ABCEGHJKLMNPRSTVXY]\d[A-Z]*\d[A-Z]\d$/;
if(regex.test(myform.zip.value)==false){
警报(“输入有效邮政编码”);
myform.zip.focus();
返回false;
}
返回true;
}
最后一个注意事项是,通常当您在正则表达式中看到
[A-Z]
时,至少需要考虑它是否应该是[A-Za-Z]
以接受大写或小写字母。我不知道加拿大邮政编码是否如此,但通常情况下,大多数表单都应接受输入,并根据需要更正大小写。这适用于所有加拿大邮政编码
^[ABCEGHJKLMNPRSTVXY]{1}\d{1}[A-Z]{1} *\d{1}[A-Z]{1}\d{1}$
这里是规则
ABCEGHJKLMNPRSTVXY这是我使用的加拿大邮政编码的有效表达式。
它的格式将严格为A0A 0A0
/^[A-Za-z]\d[A-Za-z][ -]?\d[A-Za-z]\d$/
这适用于加拿大邮政编码:
/^[a-z][0-9][a-z][- ]?[0-9][a-z][0-9]$/i
它将允许正确的X#X#X#格式,并带有空格或连字符。解决方案对于您的回答,我希望能有所帮助。谢谢你的时间
string[] inputName = new string[5];
string[] inputId = new string[5];
string[] inputMarks = new string[5];
Regex StudentId = new Regex(@"\d\d\d\d\d$");
Regex Marks = new Regex(@"\d\d$");
Regex StudentName = new Regex(@"^([a-zA-z\s]{5,10})$");
private void btnClear_Click(object sender, EventArgs e)
{
rtShowAll.Clear();
}
private void btnAdd_Click(object sender, EventArgs e)
{
string Name = txtLastName.Text;
string id = txtStudentId.Text;
string marks = txtMarks.Text;
if ((Name == "") || (!StudentName.IsMatch(Name)))
{
MessageBox.Show("space cannot be empty and enter valid characters only");
}
else if (Name != "")
{
if ((id == null) || (StudentId.IsMatch(id)))
{
MessageBox.Show("Enter valid id");
}
else if ((id != null) || (StudentId.IsMatch(id)))
{
if ((marks == null) || (!Marks.IsMatch(marks)))
{
MessageBox.Show("enter valid marks");
}
else if ((marks != null) || (Marks.IsMatch(marks)))
{
for (int i = 0; i <= 5; i++)
{
inputName[i] = Name;
inputId[i] = id;
inputMarks[i] = marks;
break;
}
}
}
}
txtLastName.Clear();
txtMarks.Clear();
txtStudentId.Clear();
}
private void btnShowAll_Click(object sender, EventArgs e)
{
string result = "";
for (int i = 0; i <= 5; i++)
{
result = inputName[i] + " " + inputId[i] + " " + inputMarks[i];
rtShowAll.Text = result;
break;
}
//list.Add(rtShowAll.Text);
//string Showall = "";
// foreach (string s in list)
// {
// Showall += s + " "+ "\n";
//}
// rtShowAll.Text = Showall;
}
private void btnSearch_Click(object sender, EventArgs e)
{
string searchId = txtStudentId.Text;
string result = "";
txtStudentId.Text = searchId;
for (int i = 0; i < 5; i++)
{
if (searchId == inputId[i])
{
result = inputName[i] + " " + inputMarks[i];
rtSearch.Text = result;
}
else if (searchId != inputId[i])
{
MessageBox.Show("Enter valid Student id");
}
}
}
private void btnModify_Click(object sender, EventArgs e)
{
string id = txtStudentId.Text;
string newmarks = "";
for (int i = 0; i < 5; i++)
{
if (id == inputId[i])
{
newmarks = txtMarks.Text;
if ((newmarks == null) || (!Marks.IsMatch(newmarks)))
{
MessageBox.Show("enter valid marks");
}
else if ((newmarks != null || (Marks.IsMatch(newmarks))))
{
inputMarks[i] = newmarks;
MessageBox.Show("marks has been modified");
}
}
}
}
}
string[]inputName=新字符串[5];
字符串[]inputId=新字符串[5];
字符串[]inputMarks=新字符串[5];
Regex StudentId=new Regex(@“\d\d\d\d$”);
正则表达式标记=新正则表达式(@“\d\d$”);
Regex StudentName=newregex(@“^([a-zA-z\s]{5,10})$”;
私有void btnClear\u单击(对象发送者,事件参数e)
{
rtShowAll.Clear();
}
私有void btnAdd_单击(对象发送者,事件参数e)
{
字符串名称=txtLastName.Text;
字符串id=txtStudentId.Text;
字符串标记=txtMarks.Text;
如果((Name==“”)| |(!StudentName.IsMatch(Name)))
{
MessageBox.Show(“空格不能为空,只能输入有效字符”);
}
else if(名称!=“”)
{
if((id==null)| |(StudentId.IsMatch(id)))
{
MessageBox.Show(“输入有效id”);
}
else如果((id!=null)| |(StudentId.IsMatch(id)))
{
如果((marks==null)| |(!marks.IsMatch(marks)))
{
MessageBox.Show(“输入有效标记”);
}
else如果((marks!=null)| |(marks.IsMatch(marks)))
{
对于(int i=0;i,{1}
业务是毫无意义的。一个[]
字符类已经是一个隐式{1}
总之,与\d
和任何其他匹配单个字符的东西一样。除此之外,这是怎么不起作用的?您是否检查了输入没有前导/尾随空格?输入和输出的示例是什么?或者它根本不起作用有效的加拿大邮政编码的规则是什么?什么测试输入不起作用regex失败了吗?根本不起作用。一个有效的邮政编码示例是T2X 1V4。我看不到在第一个代码块的任何地方调用okNumber…这段代码正在执行吗?在这种情况下,类似于^[A-Z]\d[A-Z][?\d[A-Z]\d$
。如果这个regex在您的程序中不起作用,您可能会有一个逻辑错误(true而不是false?),可能是错误地调用了正则表达式代码,或者根本没有调用它。请解释您为OP编写的代码
/^[a-z][0-9][a-z][- ]?[0-9][a-z][0-9]$/i
string[] inputName = new string[5];
string[] inputId = new string[5];
string[] inputMarks = new string[5];
Regex StudentId = new Regex(@"\d\d\d\d\d$");
Regex Marks = new Regex(@"\d\d$");
Regex StudentName = new Regex(@"^([a-zA-z\s]{5,10})$");
private void btnClear_Click(object sender, EventArgs e)
{
rtShowAll.Clear();
}
private void btnAdd_Click(object sender, EventArgs e)
{
string Name = txtLastName.Text;
string id = txtStudentId.Text;
string marks = txtMarks.Text;
if ((Name == "") || (!StudentName.IsMatch(Name)))
{
MessageBox.Show("space cannot be empty and enter valid characters only");
}
else if (Name != "")
{
if ((id == null) || (StudentId.IsMatch(id)))
{
MessageBox.Show("Enter valid id");
}
else if ((id != null) || (StudentId.IsMatch(id)))
{
if ((marks == null) || (!Marks.IsMatch(marks)))
{
MessageBox.Show("enter valid marks");
}
else if ((marks != null) || (Marks.IsMatch(marks)))
{
for (int i = 0; i <= 5; i++)
{
inputName[i] = Name;
inputId[i] = id;
inputMarks[i] = marks;
break;
}
}
}
}
txtLastName.Clear();
txtMarks.Clear();
txtStudentId.Clear();
}
private void btnShowAll_Click(object sender, EventArgs e)
{
string result = "";
for (int i = 0; i <= 5; i++)
{
result = inputName[i] + " " + inputId[i] + " " + inputMarks[i];
rtShowAll.Text = result;
break;
}
//list.Add(rtShowAll.Text);
//string Showall = "";
// foreach (string s in list)
// {
// Showall += s + " "+ "\n";
//}
// rtShowAll.Text = Showall;
}
private void btnSearch_Click(object sender, EventArgs e)
{
string searchId = txtStudentId.Text;
string result = "";
txtStudentId.Text = searchId;
for (int i = 0; i < 5; i++)
{
if (searchId == inputId[i])
{
result = inputName[i] + " " + inputMarks[i];
rtSearch.Text = result;
}
else if (searchId != inputId[i])
{
MessageBox.Show("Enter valid Student id");
}
}
}
private void btnModify_Click(object sender, EventArgs e)
{
string id = txtStudentId.Text;
string newmarks = "";
for (int i = 0; i < 5; i++)
{
if (id == inputId[i])
{
newmarks = txtMarks.Text;
if ((newmarks == null) || (!Marks.IsMatch(newmarks)))
{
MessageBox.Show("enter valid marks");
}
else if ((newmarks != null || (Marks.IsMatch(newmarks))))
{
inputMarks[i] = newmarks;
MessageBox.Show("marks has been modified");
}
}
}
}
}