PHP代码列出所有用户以及从其他表收集的总值

表A

表B

-----------------
a_id | user _a  | 
-----------------
1        |adam  |
2        |jose     |
3        |adam  |
4        |adam  |
5        |anne   |
6        |jose     |

表C

--------------------------------------
b_id | user_b   | value1 | value2 
--------------------------------------
1        |adam  | 33          | 9
2        |jose     | 46          |88
3        |adam  | 77          |21
4        |adam  | 81          |15
5        |anne   | 11          |67
6        |jose     | 45          |6

表D

--------------------------------------
c_id | user_c  | value1 | value2 
--------------------------------------
1        |adam  | 33          | 9
2        |jose     | 46          |88
3        |adam  | 77          |21
4        |adam  | 81          |15

如何查看value1和value2的总值。 示例：我希望我的列表视图页面如下所示

--------------------------------------
d_id | user_d   | value1 | value2 
--------------------------------------
1        |adam  | 33          | 9
2        |jose     | 46          |88

---

请。帮助。

这里有一种方法，可以使用SQL查询（独立于PHP中的任何处理）获得指定的结果：

---

所以这不是免费的编码服务。请展示您尝试过的内容，我们将帮助您修复。提示：使用

UNION ALL

将三个表与值组合起来，并使用

SUM（）

和

GROUP BY

计算总数。我以前曾问过，这里：

--------------------------------------------------------
user  | total value of value1 | total value of value2
---------------------------------------------------------
adam  |415                    | 99
jose    |183                     | 270
anne  |11                       | 67

SELECT t.user_t      AS `user`
     , SUM(t.value1) AS `total value of value1`
     , SUM(t.value2) AS `total value of value2`
  FROM ( SELECT b.user_b      AS user_t
              , SUM(b.value1) AS value1
              , SUM(b.value2) AS value2
           FROM table_b b 
          GROUP BY b.user_b
          UNION ALL
         SELECT c.user_c      AS user_t
              , SUM(c.value1) AS value1
              , SUM(c.value2) AS value2
           FROM table_c c 
          GROUP BY c.user_c
          UNION ALL
         SELECT d.user_d      AS user_t
              , SUM(d.value1) AS value1
              , SUM(d.value2) AS value2
           FROM table_d d 
          GROUP BY d.user_d
       ) t
 GROUP BY t.user_t
 ORDER BY 2 DESC