Php 如何在给定的结构中输出json?
我希望通过这种方式获得给定格式的json输出Php 如何在给定的结构中输出json?,php,json,codeigniter,Php,Json,Codeigniter,我希望通过这种方式获得给定格式的json输出 "free_issue": [ { "product_id": [ "44", "45", "95" ], "free_product_ids": [ "15", "118" ], "structure": { "req_
"free_issue": [
{
"product_id": [
"44",
"45",
"95"
],
"free_product_ids": [
"15",
"118"
],
"structure": {
"req_qty": "12",
"free_qty": "1"
}
}
]
第一个数组可以。但从第二个产品id和免费产品id开始,重复如下所述
"free_issue": [
{
"product_id": [
"44",
"45",
"95"
],
"free_product_ids": [
"15",
"118"
],
"structure": {
"req_qty": "12",
"free_qty": "1"
}
},
{
"product_id": [
**"44",
"45",
"95",**
"20",
"21",
"22",
"23",
"32",
"33",
"48",
"49",
"51",
"52"
],
"free_product_ids": [
**"15",
"118"**
],
"structure": {
"req_qty": "0",
"free_qty": "0"
}
},
{
"product_id": [
**"44",
"45",
"95",
"20",
"21",
"22",
"23",
"32",
"33",
"48",
"49",
"51",
"52",**
"20",
"21",
"22",
"23",
"32",
"33",
"48",
"51"
],
"free_product_ids": [
"15",
"118",
"53",
"54",
"55"
],
"structure": {
"req_qty": "12",
"free_qty": "1"
}
},
{
"product_id": [
"44",
"45",
"95",
"20",
"21",
"22",
"23",
"32",
"33",
"48",
"49",
"51",
"52",
"20",
"21",
"22",
"23",
"32",
"33",
"48",
"51",
"20",
"21",
"22",
"23",
"32",
"33",
"48",
"49",
"51",
"52"
],
"free_product_ids": [
"15",
"118",
"53",
"54",
"55",
"20",
"21",
"22",
"23",
"32",
"33",
"48"
],
"structure": {
"req_qty": "25",
"free_qty": "2"
}
}
]
如上代码中粗体所示,重复了数据。
这是我使用的查询
$product_id = array();
$free_product_id = array();
$free_issue = array();
$sql = "select eff.eff_id,eff.eff_product_typeid,eff.eff_qty,eff.eff_freeProduct_id,eff.qty from tbl_eligibleitem_for_free as eff where eff.eff_sdate <= CURDATE() and eff.`status` = 1";
$this->db->mod_select($sql);
$try = $this->db->query($sql);
foreach ($try->result() as $row)
{
$rowid = $row->eff_id;
$sql3 = "select ff.id_ff_flavor_id from tbl_flavor_free as ff where ff.ff_active = 1 and ff.ff_product_type_id = $row->eff_id and ff.ff_status = 'E'";
$query = $this->db->query($sql3);
if($query->num_rows()>0)
{
foreach ($query->result() as $row2)
{
$sql4 = "select tp.product_id from tbl_product as tp where tp.product_type_id = $row->eff_product_typeid and tp.flavour_id = $row2->id_ff_flavor_id";
$query2 = $this->db->query($sql4);
foreach ($query2->result() as $row3)
{
$product_id[] = $row3->product_id;
}
}
}
else
{
$sql4 = "select tp.product_id from tbl_product as tp where tp.product_type_id = $row->eff_product_typeid";
$query2 = $this->db->query($sql4);
foreach ($query2->result() as $row3)
{
$product_id[] = $row3->product_id;
}
}
$sql5 = "select ff.id_ff_flavor_id from tbl_flavor_free as ff where ff.ff_active = 1 and ff.ff_product_type_id = $row->eff_id and ff.ff_status = 'F'";
$fquery = $this->db->query($sql5);
if($fquery->num_rows()>0)
{
foreach ($fquery->result() as $frow2)
{
$sql6 = "select tp.product_id from tbl_product as tp where tp.product_type_id = $row->eff_freeProduct_id and tp.flavour_id = $frow2->id_ff_flavor_id";
$fquery2 = $this->db->query($sql6);
foreach ($fquery2->result() as $frow3)
{
$free_product_id[] = $frow3->product_id;
}
}
}
else
{
$sql6 = "select tp.product_id from tbl_product as tp where tp.product_type_id = $row->eff_freeProduct_id";
$fquery2 = $this->db->query($sql6);
foreach ($fquery2->result() as $frow3)
{
$free_product_id[] = $frow3->product_id;
}
}
$quantity = array(
'req_qty'=>$row->eff_qty,
'free_qty'=>$row->qty
);
$free_issue[] = array(
'product_id'=>$product_id,
'free_product_ids'=>$free_product_id,
'structure'=>$quantity);
}
return $free_issue;
$product_id=array();
$free_product_id=array();
$free_issue=array();
$sql=“从tbl\U eligibleitem\u中选择eff.eff\u id、eff.eff\u product\u typeid、eff.eff\u数量、eff.eff\u freeProduct\u id、eff.qt作为eff free as eff,其中eff.eff\u sdate eff\u id和ff.ff\u status='E';
$query=$this->db->query($sql3);
如果($query->num\u rows()>0)
{
foreach($query->result()作为$row2)
{
$sql4=“从tbl\U产品中选择tp.product\U id作为tp,其中tp.product\U type\U id=$row->eff\U product\U typeid和tp.VALUE\U id=$row2->id\U ff\U VALUE\U id”;
$query2=$this->db->query($sql4);
foreach($query2->result()作为$row3)
{
$product\U id[]=$row3->product\U id;
}
}
}
其他的
{
$sql4=“从tbl\U产品中选择tp.product\U id作为tp,其中tp.product\U type\U id=$row->eff\U product\U typeid”;
$query2=$this->db->query($sql4);
foreach($query2->result()作为$row3)
{
$product\U id[]=$row3->product\U id;
}
}
$sql5=“从tbl_flavor_free中选择ff.id_ff_flavor_id作为ff,其中ff.ff_active=1和ff.ff_product_type_id=$row->eff_id和ff.ff_status='F';
$fquery=$this->db->query($sql5);
如果($fquery->num\u rows()>0)
{
foreach($fquery->result()作为$frow2)
{
$sql6=“从tbl\U产品中选择tp.product\U id作为tp,其中tp.product\U type\U id=$row->eff\U freeProduct\U id和tp.VALUE\U id=$frow2->id\U ff\U VALUE\U id”;
$fquery2=$this->db->query($sql6);
foreach($fquery2->result()作为$frow3)
{
$free_product_id[]=$frow3->product_id;
}
}
}
其他的
{
$sql6=“从tbl\U产品中选择tp.product\U id作为tp,其中tp.product\U type\U id=$row->eff\U freeProduct\U id”;
$fquery2=$this->db->query($sql6);
foreach($fquery2->result()作为$frow3)
{
$free_product_id[]=$frow3->product_id;
}
}
$quantity=数组(
“请求数量”=>$row->eff数量,
“自由数量”=>美元行->数量
);
$free_issue[]=数组(
“产品id”=>$product\U id,
“免费产品标识”=>免费产品标识,
“结构”=>$数量);
}
退回$free_发行;
我想不出这里的问题。
请任何人帮我整理一下?数组$free\u product\u id和$product\u id在循环结束时没有重置,因此它们仍然包含它们的值 你需要重新设置它们
$free_product_id = $product_id = array();
在此修改代码谢谢!!!!!!!!!!!!!!!!!!!非常感谢…我得到了正确的数据博士再次感谢你