Php 从数据库mysql检索数据不工作
您好,我正在使用ajax使用html下拉列表的onchange事件 在我正在使用的代码中,当我更改 放下 但它不起作用。可能出了什么问题 这是密码Php 从数据库mysql检索数据不工作,php,javascript,html,ajax,Php,Javascript,Html,Ajax,您好,我正在使用ajax使用html下拉列表的onchange事件 在我正在使用的代码中,当我更改 放下 但它不起作用。可能出了什么问题 这是密码 <html> <head> <script> function showUser( str ) { if ( str == "" ) { document.getElementById("txtHint").innerHTML=""; ret
<html>
<head>
<script>
function showUser( str ) {
if ( str == "" ) {
document.getElementById("txtHint").innerHTML="";
return;
}
if ( window.XMLHttpRequest ) {
// code for IE7+, Firefox, Chrome, Opera, Safari
xmlhttp=new XMLHttpRequest();
} else {
// code for IE6, IE5
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if ( xmlhttp.readyState==4 && xmlhttp.status == 200 ) {
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET", "getuser.php?q=" + str, true);
xmlhttp.send();
}
</script>
</head>
<body>
<form>
<?php
mysql_connect('localhost', 'tiger', 'tiger');
mysql_select_db('theaterdb');
$sql = "select theater_name from theater;";
$result = mysql_query($sql);
echo "<select name='theater_name' id='course' onchange='showUser(this.value);'>";
while ( $row = mysql_fetch_array( $result ) ) {
echo "<option value='" . $row['theater_name'] ."'>" . $row['theater_name']. "</option>";
}
echo "</select>";
?>
</form>
<br>
<div id="txtHint"><b>Info</b></div>
</body>
</html>
函数showUser(str){
如果(str==“”){
document.getElementById(“txtHint”).innerHTML=“”;
返回;
}
if(window.XMLHttpRequest){
//IE7+、Firefox、Chrome、Opera、Safari的代码
xmlhttp=新的XMLHttpRequest();
}否则{
//IE6、IE5的代码
xmlhttp=新的ActiveXObject(“Microsoft.xmlhttp”);
}
xmlhttp.onreadystatechange=函数(){
if(xmlhttp.readyState==4&&xmlhttp.status==200){
document.getElementById(“txtHint”).innerHTML=xmlhttp.responseText;
}
}
open(“GET”、“getuser.php?q=“+str,true”);
xmlhttp.send();
}
信息
getuser.php的代码
<?php
$q = $_GET["q"];
$con = mysqli_connect("localhost", "tiger", "tiger", "theaterdb");
if ( !$con ) {
die('Could not connect: ' . mysqli_error( $con ) );
}
mysqli_select_db( $con );
$sql = "SELECT address FROM theater WHERE theater_name = '".$q."'";
$result = mysqli_query( $con, $sql );
echo "<table border='1'>
<tr>
<th>Firstname</th>
</tr>";
while( $row = mysqli_fetch_array( $result ) ) {
echo "<tr>";
echo "<td>" . $row['address'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
<?php
$q = strtolower(trim($_GET["q"]));
try {
$dbh = new PDO('mysql:dbname=theaterdb;host=localhost','tiger','tiger');
} catch (PDOException $e) {
echo 'Connection failed: ' . $e->getMessage();
}
$sql = 'SELECT address FROM theater WHERE LOWER(theater_name) = :q';
$sth = $dbh->prepare($sql);
$sth->bindValue(':q', $q);
$sth->execute();
echo "<table border='1'><tr><th>Firstname</th></tr>";
while($row = $sth->fetch(PDO::FETCH_ASSOC)) {
echo "<tr>";
echo "<td>" . $row['address'] . "</td>";
echo "</tr>";
}
echo "</table>";
$dbh = null;
我无法理解为什么您在这两个php文件中都连接了数据库? 我建议你访问下面的链接
好的,我已经稍微调整了你的文件,你不应该再使用mysql或mysqli函数了,只是不要。。。当然,您不应该在一个文件中使用mysql函数,在另一个文件中使用mysqli函数。。。我已经将它们转换为使用PDO,您的脚本现在不受SQL注入的影响,而且据我所知,它工作得很好 index.html
<html>
<head>
<script>
function showUser(str) {
if(str=="") {
document.getElementById("txtHint").innerHTML="";
return;
}
if(window.XMLHttpRequest) {
xmlhttp=new XMLHttpRequest();
} else {
xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
}
xmlhttp.onreadystatechange = function() {
if(xmlhttp.readyState==4 && xmlhttp.status==200) {
document.getElementById("txtHint").innerHTML=xmlhttp.responseText;
}
}
xmlhttp.open("GET","getuser.php?q="+str,true);
xmlhttp.send();
}
</script>
</head>
<body>
<form>
<?php
try {
$dbh = new PDO('mysql:dbname=theaterdb;host=localhost','tiger','tiger');
} catch (PDOException $e) {
echo 'Connection failed: ' . $e->getMessage();
}
$sql = "SELECT theater_name FROM theater;";
$sth = $dbh->prepare($sql);
$sth->execute();
echo "<select name='theater_name' id='course' onchange='showUser(this.value);'>";
while($row = $sth->fetch(PDO::FETCH_ASSOC)) {
echo "<option value='" . $row['theater_name'] ."'>" . $row['theater_name']. "</option>";
}
echo "</select>";
?>
</form>
<br>
<div id="txtHint"><b>Info</b></div>
</body>
</html>
函数showUser(str){
如果(str==“”){
document.getElementById(“txtHint”).innerHTML=“”;
返回;
}
if(window.XMLHttpRequest){
xmlhttp=新的XMLHttpRequest();
}否则{
xmlhttp=新的ActiveXObject(“Microsoft.xmlhttp”);
}
xmlhttp.onreadystatechange=函数(){
if(xmlhttp.readyState==4&&xmlhttp.status==200){
document.getElementById(“txtHint”).innerHTML=xmlhttp.responseText;
}
}
open(“GET”、“getuser.php?q=“+str,true”);
xmlhttp.send();
}
信息
getuser.php
<?php
$q = $_GET["q"];
$con = mysqli_connect("localhost", "tiger", "tiger", "theaterdb");
if ( !$con ) {
die('Could not connect: ' . mysqli_error( $con ) );
}
mysqli_select_db( $con );
$sql = "SELECT address FROM theater WHERE theater_name = '".$q."'";
$result = mysqli_query( $con, $sql );
echo "<table border='1'>
<tr>
<th>Firstname</th>
</tr>";
while( $row = mysqli_fetch_array( $result ) ) {
echo "<tr>";
echo "<td>" . $row['address'] . "</td>";
echo "</tr>";
}
echo "</table>";
mysqli_close($con);
?>
<?php
$q = strtolower(trim($_GET["q"]));
try {
$dbh = new PDO('mysql:dbname=theaterdb;host=localhost','tiger','tiger');
} catch (PDOException $e) {
echo 'Connection failed: ' . $e->getMessage();
}
$sql = 'SELECT address FROM theater WHERE LOWER(theater_name) = :q';
$sth = $dbh->prepare($sql);
$sth->bindValue(':q', $q);
$sth->execute();
echo "<table border='1'><tr><th>Firstname</th></tr>";
while($row = $sth->fetch(PDO::FETCH_ASSOC)) {
echo "<tr>";
echo "<td>" . $row['address'] . "</td>";
echo "</tr>";
}
echo "</table>";
$dbh = null;
你在$result
中得到了什么<代码>打印($result)
和$q
echo$q
首先解释“不工作”,确保提供了用户名和密码correct@Shadowfax不,当我打印时,我没有得到这些值。您是否在xmlhttp.open(“GET”,“getuser.php?q=“+str,true”)之前得到str
的值代码>线路谢谢@Garry焊接