Php 如何在会话中存储整个$u POST变量

我有下拉选择，当我点击提交按钮时，它会根据下拉列表的值显示记录。它工作正常，但当我刷新app_list2.php时，它什么也不显示。我想保留app_list2.php中显示的记录。如何在会话中存储所有$\u POST值

    <?php
    $mysqli = new mysqli("localhost", "root", "", "app");
    if(isset($_POST['submit'])){
    $drop = $_POST['drop_1'];
    $tier_two = $_POST['tier_two'];

    $where = "WHERE app_cn='$drop' AND app_plan_no='$tier_two'";

$result1 = $mysqli->query("
    SELECT *, SUM(unit_cost*quantity) AS total_amount, SUM(unit_cost*1st_quarter) AS 1st_quarter_total, SUM(unit_cost*2nd_quarter) AS 2nd_quarter_total, SUM(unit_cost*3rd_quarter) AS 3rd_quarter_total,
    SUM(unit_cost*4th_quarter) AS 4th_quarter_total, SUM((quantity)-(1st_q_qty_del+2nd_q_qty_del+3rd_q_qty_del+4th_q_qty_del)) AS balance
    FROM app 
    $where 
    GROUP BY counter ORDER BY counter
");
?>

<?php
echo'<table id="tfhover" cellspacing="0" class="tablesorter" style="text-transform:uppercase;">
        <thead>
            <tr>
        <th>Item</th>
        <th>Description</th>
        <th>Fund Source</th>
        <th>Unit</th>
        <th>Unit Cost</th>
    </tr>
        </thead>';
        echo'<tbody>';
$i=1;
while($row = $result1->fetch_assoc()){
if($row['app_cn'] != '')
 {
 echo'<tr>
    <td>'.$row['item_name'].'</td>
        <td>'.$row['item_description'].'</td>
    <td>'.$row['fund_source'].'</td>
        <td>'.$row['unit'].'</td>
        <td>'.number_format($row['unit_cost'], 2, '.', ',').'</td>
       </tr>';
    }
        }
    echo "</tbody></table>";
}
?>

试试这个代码

<?php

    ob_start();
    session_start();
        $mysqli = new mysqli("localhost", "root", "", "app");



    if(isset($_POST['submit'])){

    //unset the session value 
    $_SESSION['content'] = '';

    $drop = $_POST['drop_1'];
    $tier_two = $_POST['tier_two'];

    $where = "WHERE app_cn='$drop' AND app_plan_no='$tier_two'";

$result1 = $mysqli->query("
    SELECT *, SUM(unit_cost*quantity) AS total_amount, SUM(unit_cost*1st_quarter) AS 1st_quarter_total, SUM(unit_cost*2nd_quarter) AS 2nd_quarter_total, SUM(unit_cost*3rd_quarter) AS 3rd_quarter_total,
    SUM(unit_cost*4th_quarter) AS 4th_quarter_total, SUM((quantity)-(1st_q_qty_del+2nd_q_qty_del+3rd_q_qty_del+4th_q_qty_del)) AS balance
    FROM app 
    $where 
    GROUP BY counter ORDER BY counter
");
?>

<?php
echo'<table id="tfhover" cellspacing="0" class="tablesorter" style="text-transform:uppercase;">
        <thead>
            <tr>
        <th>Item</th>
        <th>Description</th>
        <th>Fund Source</th>
        <th>Unit</th>
        <th>Unit Cost</th>
    </tr>
        </thead>';
        echo'<tbody>';
$i=1;
while($row = $result1->fetch_assoc()){
if($row['app_cn'] != '')
 {
 echo'<tr>
    <td>'.$row['item_name'].'</td>
        <td>'.$row['item_description'].'</td>
    <td>'.$row['fund_source'].'</td>
        <td>'.$row['unit'].'</td>
        <td>'.number_format($row['unit_cost'], 2, '.', ',').'</td>
       </tr>';
    }
        }
    echo "</tbody></table>";

    $sPageContent = ob_get_clean();
    $_SESSION['content']    =   $sPageContent;

}else{

    if (isset($_SESSION['content'])){
        echo $_SESSION['content'];
    }


}
?>

检查错误，似乎是php错误。并清理您的查询字段没有错误，我想是因为它没有确定记录的id吗？这是因为在刷新时，您将失去对已发布值的跟踪，所以不会有任何结果appear@leobali是的，即使我刷新了页面，我怎样才能得到发布的值呢？在尝试此代码之前，将所有的发布值存储到sessiontry以清除缓存，并在刷新之前调试第一次显示的会话值..页面内容是否存储在值中？抱歉，响应太晚，我已经尝试了此代码。当我点击app_list.php中的提交按钮时，它不会显示任何内容。但当我刷新页面时，它会显示记录。为什么呢？