似乎无法使我的php联系人表单正常工作

我有一个叫做联系我们html的表单

<section id="contact-page">
    <div class="container">
        <div class="row contact-wrap"> 
            <div class="status alert alert-success" style="display: none"></div>
            <form id="main-contact-form" class="contact-form" name="contact-form" method="post" action="sendemail.php">
                <div class="col-sm-5 col-sm-offset-1">
                    <div class="form-group">
                        <label>Name *</label>
                        <input type="text" name="name" class="form-control" required="required">
                    </div>
                    <div class="form-group">
                        <label>Email *</label>
                        <input type="email" name="email" class="form-control" required="required">
                    </div>                       
                </div>
                <div class="col-sm-5">
                    <div class="form-group">
                        <label>Subject *</label>
                        <input type="text" name="subject" class="form-control" required="required">
                    </div>
                    <div class="form-group">
                        <label>Message *</label>
                        <textarea name="message" id="message" required="required" class="form-control" rows="8" placeholder="Please add who referred you if applicable"></textarea>
                    </div>                        
                    <div class="form-group">
                        <button type="submit" name="submit" class="btn btn-primary btn-lg" required="required">Submit Message</button>
                    </div>
                </div>
            </form> 
        </div><!--/.row-->
    </div><!--/.container-->
</section><!--/#contact-page-->

名字*
电子邮件*
主题*
信息*
提交消息

然后是sendmail.php

<?php
header('Content-type: application/json');
$status = array(
    'type'=>'success',
    'message'=>'Thank you for contact us. As early as possible  we will contact you '
);

$name = $_POST['name']; 
$email = $_POST['email']; 
$subject = $_POST['subject']; 
$message = $_POST['message']; 

$email_from = $email;
$email_to = 'myemail@gmail.com';

$body = 'Name: ' . $name . "\n\n" . 'Email: ' . $email . "\n\n" . 'Subject: ' . $subject . "\n\n" . 'Message: ' . $message;

$success = @mail($email_to, $subject, $body, 'From: <'.$email_from.'>');

echo json_encode($status);
die;

---

您是否正确获取了$\u POST变量？在php文件顶部尝试以下操作：
print\r（$\u POST）；死亡以查看您得到了什么。如果您对此有问题，请尝试将此属性添加到您的
标记：
enctype=“multipart/form data”>
之后@charles您可以使用您的ajax函数吗。@EduardoEscobar它只显示“undefined”，不再发送电子邮件您确定这不是像白色背景上的白色文本这样简单的东西吗？