Php 尝试显示旋转木马滑块上显示的图像时出现问题

我目前正在尝试将它设置为我的数据库存储图像名称（如slider1.jpg）的位置，然后从数据库中检索图像名称，但问题是当我从表中选择*all时，它只显示表中的第一个链接。关于如何在代码中解决这个问题，有什么想法吗

这是我的PHP：

    <?php
        //Gets Links
    $stmt = $DB_con->prepare('SELECT * FROM slider');
    $stmt->execute();
if($stmt->rowCount() > 0)
{
     $row=$stmt->fetch(PDO::FETCH_ASSOC);

        extract($row);
}

?>  

这是我的旋转木马滑块

 <header>
      <div id="carouselExampleIndicators" class="carousel slide" data-ride="carousel">
        <ol class="carousel-indicators">
          <li data-target="#carouselExampleIndicators" data-slide-to="0" class="active"></li>
          <li data-target="#carouselExampleIndicators" data-slide-to="1"></li>
          <li data-target="#carouselExampleIndicators" data-slide-to="2"></li>
        </ol>
        <div class="carousel-inner" role="listbox">
          <!-- Slide One - Set the background image for this slide in the line below -->
          <div class="carousel-item active" style="background-image: url('images/slider/<?php echo $row['link'];?>')">
            <div class="carousel-caption d-none d-md-block">
              <h3>First Slide</h3>
              <p>This is a description for the first slide.</p>
            </div>
          </div>
          <!-- Slide Two - Set the background image for this slide in the line below -->
          <div class="carousel-item" style="background-image: url('images/slider/<?php echo $row['link'];?>')">
            <div class="carousel-caption d-none d-md-block">
              <h3>Second Slide</h3>
              <p>This is a description for the second slide.</p>
            </div>
          </div>
          <!-- Slide Three - Set the background image for this slide in the line below -->
          <div class="carousel-item" style="background-image: url('images/slider/<?php echo $row['link'];?>')">
            <div class="carousel-caption d-none d-md-block">
              <h3>Third Slide</h3>
              <p>This is a description for the third slide.</p>
            </div>
          </div>
        </div>
        <a class="carousel-control-prev" href="#carouselExampleIndicators" role="button" data-slide="prev">
          <span class="carousel-control-prev-icon" aria-hidden="true"></span>
          <span class="sr-only">Previous</span>
        </a>
        <a class="carousel-control-next" href="#carouselExampleIndicators" role="button" data-slide="next">
          <span class="carousel-control-next-icon" aria-hidden="true"></span>
          <span class="sr-only">Next</span>
        </a>
      </div>
    </header>

您需要利用结果上的循环，以便可以使用数据库查询中的新$行构建每张幻灯片：

<?php
// build a clean array of slides from the db grab
$stmt = $DB_con->prepare('SELECT * FROM slider');
$stmt->execute();
$slides = [];
if($stmt->rowCount() > 0) {
    $slides = $stmt->fetchAll(PDO::FETCH_ASSOC);
}
?>

.... starter html ....

    <ol class="carousel-indicators">
       <?php foreach($slides as $i => $slide) { ?>
          <li data-target="#carouselExampleIndicators" 
              data-slide-to="<?php echo $i;?>" 
              class="<?php echo (!$i?'active':'');?>"></li>
       <?php }?>
    </ol>

.... more html ....

<div class="carousel-inner" role="listbox">
   <?php foreach($slides as $i => $slide) { ?>

      <div class="carousel-item <?php echo (!$i?'active':'');?>" 
           style="background-image: url('images/slider/<?php echo $slide['link'];?>')">
        <div class="carousel-caption d-none d-md-block">
          <h3><?php echo $slide['slide_name'];?></h3>
          <p><?php echo $slide['slide_desc'];?></p>
        </div>
      </div>

   <?php } ?>
</div>

.... the rest of your html output ....


.... 初学者html。。。。

.... html输出的其余部分。。。。
我尝试了那个代码，但什么也没发生。只有大量的空白。当我将“div class=“carousel time active”放在旋转木马上时，它会同时显示所有图像，但不会显示在旋转木马中。我将幻灯片描述字段更改为幻灯片描述，将幻灯片名称字段改为幻灯片名称active，在旋转木马项目和控件上，这将是加载页面时的第一张幻灯片。没关系，我一开始就不知道如何从数据库中提取数据！谢谢你帮助我！