Php 如何使用with语句对关系表应用筛选器
我编写了一个代码来过滤关系数据,但并没有得到一个好的结果。这是代码。父查询和与查询一起独立工作Php 如何使用with语句对关系表应用筛选器,php,laravel,filter,laravel-query-builder,Php,Laravel,Filter,Laravel Query Builder,我编写了一个代码来过滤关系数据,但并没有得到一个好的结果。这是代码。父查询和与查询一起独立工作 public function get(Request $request, Company $company, Survey $survey) { $this->authorize('update', $survey->company); $search = $request->get('search'); $query = EsAnswer::where([
public function get(Request $request, Company $company, Survey $survey)
{
$this->authorize('update', $survey->company);
$search = $request->get('search');
$query = EsAnswer::where(['company_id' => $company->id, 'survey_id' => $survey->id])
->orderByDesc('created_at')
->with(['employee'=> function ($q) use($search) {
$q->where('first_name', 'LIKE', "%{$search}%");
$q->orwhere('last_name', 'LIKE', "%{$search}%");
$q->select('id', 'first_name', 'last_name');
}]);
if ($request->has('start_date')) {
$query->whereDate('created_at', '>=', $request->start_date);
}
if ($request->has('end_date')) {
$query->whereDate('created_at', '<=', $request->end_date);
}
$answers = $query->get()->groupBy('submission_id');
// ->paginate('100');
return $answers;
}
我得到的回应是:
{
"id": 2,
"company_id": 1,
"employee_id": 1,
"survey_id": 2,
"es_question_id": 1,
"answer": "done",
"submission_id": "1",
"mark_as_read": 1,
"created_at": "2020-08-19 12:18:25",
"updated_at": "2020-08-26 06:55:21",
"employee": {
"id": 1,
"first_name": "Baseapp",
"last_name": "saw"
}
}
当我尝试按另一个表中的员工姓名进行搜索时,如果数据存在,则应过滤数据并给出响应,但如果员工姓名或搜索数据不存在,则数据不应给出任何响应。如何处理
{
"search":"sure"
}
{
"id": 2,
"company_id": 1,
"employee_id": 1,
"survey_id": 2,
"es_question_id": 1,
"answer": "done",
"submission_id": "1",
"mark_as_read": 1,
"created_at": "2020-08-19 12:18:25",
"updated_at": "2020-08-26 06:55:21",
"employee": null
}
此处数据为空,但为什么显示父数据。请帮助并提供另一种使用关系数据过滤的方法。使用whereHas()
函数
$query=EsAnswer::with('employee:id,first\u name,last\u name')
->其中(['company\u id'=>$company->id,'survey\u id'=>$survey->id])
->whereHas('employee',函数($query)use($search){
$query->where('first_name','LIKE',“%$search%”)
->或where('last_name','LIKE',“%$search%”);
})
->orderByDesc('created_at');
ref link它使用whereHas,然后使用:
$query = EsAnswer::where(['company_id' => $company->id, 'survey_id' => $survey->id])
->orderByDesc('created_at')
->whereHas('employee', function ($q) use($search) {
return $q->where('first_name', 'LIKE', "%{$search}%")
->orwhere('last_name', 'LIKE', "%{$search}%");
})->with(['employee' => function ($q){
$q->select('id', 'first_name', 'last_name');
}]);
我们用于在相关表中进行筛选。所以像这样使用它
$query = EsAnswer::with('employee:id,first_name,last_name')
->where(['company_id' => $company->id, 'survey_id' => $survey->id])
->whereHas('employee', function($query) use($search) {
$query->where('first_name', 'LIKE', "%{$search}%")
->orwhere('last_name', 'LIKE', "%{$search}%");
})
->orderByDesc('created_at');
这将在相关表中搜索,如果没有找到任何内容,则返回null。我为数据添加了优雅的方式。你也应该看看这个。答案没有用,两者都是一样的。我希望,若我想按员工姓名搜索,那个么关系数据应该过滤,否则结果为空。但这里仅查询筛选员工模型。
$query = EsAnswer::with('employee:id,first_name,last_name')
->where(['company_id' => $company->id, 'survey_id' => $survey->id])
->whereHas('employee', function($query) use($search) {
$query->where('first_name', 'LIKE', "%{$search}%")
->orwhere('last_name', 'LIKE', "%{$search}%");
})
->orderByDesc('created_at');