php中嵌入的html条件if语句

我觉得这应该很简单，但我没有得到我想要的结果。我有一个电子邮件注册表格，可以在我所有的网站上显示。如果他们碰巧以商店代码

ama\br

访问我的网站，电子邮件注册就会消失。这很好，而且有效。我的

elseif

语句与在所有门店视图中显示的表单不同，我希望此新表单仅在其门店代码

ama_ca

时显示。它对我不起作用，我看不出我的代码有任何问题。请帮忙。多谢各位

            <?php if (Mage::app()->getStore()->getCode() != "ama_br"):?>
                <ul>
                    <li><?php echo $this->__('Email Sign Up')?></li>
                    <li>
                        <form action="<?php echo $this->getUrl('email_preferences')?>" method="get" id="newsletter-validate-detail">
                            <input name="email" type="text" id="newsletter" placeholder="<?php echo $this->__('Enter Email address')?>" title="<?php echo $this->__('Enter Email address')?>' class="required-entry validate-email">
                            <button class="submit">+</button>
                            <input type="hidden" name="source" value="nt">
                        </form>
                    </li>
                    <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo')?></li>
                </ul>

            <?php elseif (Mage::app()->getStore()->getCode() == "ama_ca"):?>
                <ul>
                    <li><?php echo $this->__('Email Sign Up')?></li>
                    <li>
                <form method="post" action="http://enews.******.com/q/9MNK4U4iV9Mutb9YzTxF2zRWDIPgKoX0F0" accept-charset="UTF-8">
                        <input type="hidden" name="crvs" value="6hZNXcISD79ac2Empmsr2az_B3Qc5osTNmkOdNHleqhPIYmsxEOe6PbgaUo-3WBn_Vbgorrbk4qjekx7w4tljA">
                        <input type="hidden" name="CheckBox.Source.ca_footer" value="on">
                        <input name="email" type="text" id="newsletter" placeholder="Enter Email address" title="Enter Email address' class=" required-entry="">
                        <input type="hidden" id="submit" value="Sign Up">
                        </form>
                    </li>
                    <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo')?></li>
                </ul>
            <?php endif;?>

说明
你做的每一件事都是对的，但你只是错过了一个诀窍仔细看看你的if语句逻辑，如果你的代码不等于ama_br，也就是说它可以等于ama_ca，因此它将在if语句中显示ama_ca的形式，以及ama_br中的任何其他字符串，因此您试图在代码上显示的表单等于ama_ca未显示。请尝试以下操作之一，它将解决您的查询

代码

        <?php if (Mage::app()->getStore()->getCode() == "ama_ca"): ?>
          <ul>
            <li><?php echo $this->__('Email Sign Up') ?></li>
            <li>
            <form method="post" action="http://enews.******.com/q/9MNK4U4iV9Mutb9YzTxF2zRWDIPgKoX0F0" accept-charset="UTF-8">
            <input type="hidden" name="crvs" value="6hZNXcISD79ac2Empmsr2az_B3Qc5osTNmkOdNHleqhPIYmsxEOe6PbgaUo-3WBn_Vbgorrbk4qjekx7w4tljA">
            <input type="hidden" name="CheckBox.Source.ca_footer" value="on">
            <input name="email" type="text" id="newsletter" placeholder="Enter Email address" title="Enter Email address' class=" required-entry="">
            <input type="hidden" id="submit" value="Sign Up">
            </form>
            </li>
           <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo') ?></li>
         </ul>

        <?php elseif (Mage::app()->getStore()->getCode() != "ama_br"): ?>
          <ul>
            <li><?php echo $this->__('Email Sign Up') ?></li>
            <li>
              <form action="<?php echo $this->getUrl('email_preferences') ?>" method="get" id="newsletter-validate-detail">
              <input name="email" type="text" id="newsletter" placeholder="<?php echo $this->__('Enter Email address') ?>" title="<?php echo $this->__('Enter Email address') ?>' class="required-entry validate-email">
                   <button class="submit">+</button>
              <input type="hidden" name="source" value="nt">
              </form>
              </li>
              <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo') ?></li>
             </ul>
        <?php endif; ?>











逻辑。只执行
if
的一个块。因为你正在做一个
=在第一个测试中测试，然后
'ama_ca'！='ama\u br'
为真，该块执行，完全跳过后面的
=='ama\u ca'
一个。首先检查
ama\u ca
。@此方法参考我的答案，它将解决您的查询anks@MarcB，我不知道该逻辑是如何工作的。多谢各位*谢谢你@Ahmer。我使用的第一个答案是基于逻辑的工作原理和更少的代码。
       <?php if (Mage::app()->getStore()->getCode() != "ama_br" && Mage::app()- >getStore()->getCode() != "ama_ca"): ?>
          <ul>
           <li><?php echo $this->__('Email Sign Up') ?></li>
            <li>
            <form action="<?php echo $this->getUrl('email_preferences') ?>" method="get" id="newsletter-validate-detail">
            <input name="email" type="text" id="newsletter" placeholder="<?php echo $this->__('Enter Email address') ?>" title="<?php echo $this->__('Enter Email address') ?>' class="required-entry validate-email">
                   <button class="submit">+</button>
                   <input type="hidden" name="source" value="nt">
            </form>
       </li>
       <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo') ?></li>
      </ul>

      <?php elseif (Mage::app()->getStore()->getCode() == "ama_ca"): ?>
      <ul>
          <li><?php echo $this->__('Email Sign Up') ?></li>
      <li>
        <form method="post" action="http://enews.******.com/q/9MNK4U4iV9Mutb9YzTxF2zRWDIPgKoX0F0" accept-charset="UTF-8">
            <input type="hidden" name="crvs" value="6hZNXcISD79ac2Empmsr2az_B3Qc5osTNmkOdNHleqhPIYmsxEOe6PbgaUo-3WBn_Vbgorrbk4qjekx7w4tljA">
            <input type="hidden" name="CheckBox.Source.ca_footer" value="on">
            <input name="email" type="text" id="newsletter" placeholder="Enter Email address" title="Enter Email address' class=" required-entry="">
            <input type="hidden" id="submit" value="Sign Up">
        </form>
    </li>
       <li class="footer-promo"><?php echo $this->getChildHtml('footer_promo')  ?></li>
    </ul>
    <?php endif; ?>