PHP-基于值的Merge 2多维数组
目前,我有两个多维数组,我希望将它们组合成一个巨大的数组,其中数组1中的值名称与数组2中的值名称匹配。 阵列的外观如下所示PHP-基于值的Merge 2多维数组,php,arrays,merge,Php,Arrays,Merge,目前,我有两个多维数组,我希望将它们组合成一个巨大的数组,其中数组1中的值名称与数组2中的值名称匹配。 阵列的外观如下所示 Array1 ( [0] => Array ( [id] => 1 [name] => test1 [desc] => test_desc [quantity] => 3 ) [1] => Ar
Array1
(
[0] => Array
(
[id] => 1
[name] => test1
[desc] => test_desc
[quantity] => 3
)
[1] => Array
(
[id] => 2
[name] => test2
[desc] => test_desc
[quantity] => 33
)
)
Array2
(
[0] => Array
(
[holder] => 'John'
[name] => test1
[desc] => test_desc
[location] => ATL
)
[1] => Array
(
[holder] => 'Jackie'
[name] => test3
[desc] => test_desc
[location] => SF
)
)
我希望合并array1中的“name”列与array2中的“name”列相匹配的数组,并将数组1和2中的列合并到最终数组中。这应该看起来像
FinalArray
(
[0] => Array
(
[id] => 1
[holder] => 'John'
[name] => test1
[desc] => test_desc
[location] => ATL
[quantity] => 3
)
[1] => Array
(
[holder] => 'Jackie'
[name] => test3
[desc] => test_desc
[location] => SF
)
[2] => Array
(
[id] => 2
[name] => test2
[desc] => test_desc
[quantity] => 33
)
)
其中,“test1”将两个数组中的不同列合并到“FinalArray”中的新数组中。我试着研究一些关于数组合并和数组合并递归的想法,但我不完全确定我是否走在了正确的方向上。提前谢谢。像这样试试
$array1=[['id' => 1,'name' => 'test1','desc' => 'test_desc','quantity' => 3],
['id' => 2,'name' => 'test2','desc' => 'test_desc','quantity' => 33]];
$array2=[['holder' => 'John','name' => 'test1','desc' => 'test_desc','location' => 'ATL'],
['holder' => 'Jackie','name' => 'test3','desc' => 'test_desc','location' => 'SF']];
$final=[];
foreach ($array1 as $key1=>$data1){
foreach ($array2 as $key2=>$data2){
if($data1['name']==$data2['name']){
$final[]=$data1+$data2;
unset($array1[$key1]);
unset($array2[$key2]);
}
}
}
if(!empty($array1)){
foreach ($array1 as $value){
$final[]=$value;
}
}
if(!empty($array2)){
foreach ($array2 as $value){
$final[]=$value;
}
}
它将给出如下输出:
像这样试试
$array1=[['id' => 1,'name' => 'test1','desc' => 'test_desc','quantity' => 3],
['id' => 2,'name' => 'test2','desc' => 'test_desc','quantity' => 33]];
$array2=[['holder' => 'John','name' => 'test1','desc' => 'test_desc','location' => 'ATL'],
['holder' => 'Jackie','name' => 'test3','desc' => 'test_desc','location' => 'SF']];
$final=[];
foreach ($array1 as $key1=>$data1){
foreach ($array2 as $key2=>$data2){
if($data1['name']==$data2['name']){
$final[]=$data1+$data2;
unset($array1[$key1]);
unset($array2[$key2]);
}
}
}
if(!empty($array1)){
foreach ($array1 as $value){
$final[]=$value;
}
}
if(!empty($array2)){
foreach ($array2 as $value){
$final[]=$value;
}
}
它将给出如下输出:
再来一个解决方案
function merge_by_name(array $arr1, array $arr2) {
$result = [];
foreach ($arr1 as $value) {
$key = array_search($value['name'], array_column($arr2, 'name'));
if($key !== false) {
$result[] = array_merge($value, $arr2[$key]);
unset($arr2[$key]);
} else {
$result[] = $value;
}
}
$result = array_merge($result, $arr2);
return $result;
}
试验 结果
array (
0 =>
array (
'id' => 1,
'name' => 'test1',
'desc' => 'test_desc',
'quantity' => 3,
'holder' => 'John',
'location' => 'ATL',
),
1 =>
array (
'id' => 2,
'name' => 'test2',
'desc' => 'test_desc',
'quantity' => 33,
),
2 =>
array (
'holder' => 'Jackie',
'name' => 'test3',
'desc' => 'test_desc',
'location' => 'SF',
),
)
还有一个解决方案
function merge_by_name(array $arr1, array $arr2) {
$result = [];
foreach ($arr1 as $value) {
$key = array_search($value['name'], array_column($arr2, 'name'));
if($key !== false) {
$result[] = array_merge($value, $arr2[$key]);
unset($arr2[$key]);
} else {
$result[] = $value;
}
}
$result = array_merge($result, $arr2);
return $result;
}
试验 结果
array (
0 =>
array (
'id' => 1,
'name' => 'test1',
'desc' => 'test_desc',
'quantity' => 3,
'holder' => 'John',
'location' => 'ATL',
),
1 =>
array (
'id' => 2,
'name' => 'test2',
'desc' => 'test_desc',
'quantity' => 33,
),
2 =>
array (
'holder' => 'Jackie',
'name' => 'test3',
'desc' => 'test_desc',
'location' => 'SF',
),
)
让我们看看你到目前为止都做了些什么