Php 为什么backButton HTML按钮的名称或值不显示在$\u POST中?
尝试检测用户何时单击“取消”,但使用var\u export($\u POST)时的$\u POST输出:-Php 为什么backButton HTML按钮的名称或值不显示在$\u POST中?,php,html,back-button,Php,Html,Back Button,尝试检测用户何时单击“取消”,但使用var\u export($\u POST)时的$\u POST输出:- array ( 'descr' => '', 'formSubmitted' => '1', 'backButton_x' => '36', 'backButton_y' => '15', ) Notice: Undefined index: backButton in /home/mholt/development/BusinessPortic
array (
'descr' => '',
'formSubmitted' => '1',
'backButton_x' => '36',
'backButton_y' => '15',
)
Notice: Undefined index: backButton in /home/mholt/development/BusinessPortico/class/requestHandler.class.php on line 81
以下是HTML:-
<form method="post" class="cssform_dialog" enctype="multipart/form-data">
<div id="dialogContent"></div>
<div id="dialogFooter">
<div class="wrapperLeft"><input type="image" name="nextButton" id="nextButton" value="Yes" src="../new_assets/images/button-save.jpg"/></div>
<div class="wrapperRight"><input value="Cancel" name="backButton" type="image" src="../new_assets/images/button-cancel.jpg"/></div>
<input type="hidden" name="formSubmitted" value="1"/>
</div>
</form>
因为它是
type='image'
-服务器端映像映射
对该规范的严格阅读表明,浏览器应该包含该规范的值,但并非所有浏览器都包含该规范的值,因此有些浏览器只发送坐标
您可以查找name.x(或PHP中的name_x),也可以不使用图像输入,因为它不是专门为它设计的。我不明白,因为我在其他实例中也可以使用它。如何使用Php检测“backButton”已被按下?例如,如果($_POST['backButton]])//做点什么