从php数组创建新日期
我正在尝试从数组创建一个日期。有什么功能可以实现这一点吗?我所知道的是我可以访问字段并从中创建日期从php数组创建新日期,php,date,datetime,Php,Date,Datetime,我正在尝试从数组创建一个日期。有什么功能可以实现这一点吗?我所知道的是我可以访问字段并从中创建日期 'endDate' => array( 'month' => '05', 'day' => '30', 'year' => '2017', 'hour' => '10', 'min' => '48', 'meridian' => 'pm' ) 我使用D
'endDate' => array(
'month' => '05',
'day' => '30',
'year' => '2017',
'hour' => '10',
'min' => '48',
'meridian' => 'pm'
)
我使用
DateTime::createFromFormat
和vsprintf
从数组构造时间字符串,并得出以下结论:
<?php
$endDate = array(
'month' => '05',
'day' => '30',
'year' => '2017',
'hour' => '10',
'min' => '48',
'meridian' => 'pm'
);
$date = DateTime::createFromFormat('d/m/Y h:i a', vsprintf('%s/%s/%s %s:%s %s', [
$endDate['day'],
$endDate['month'],
$endDate['year'],
$endDate['hour'],
$endDate['min'],
$endDate['meridian'],
]));
echo $date->format('d/m/Y h:i a');
实际上,您甚至可能不需要使用DateTime
,但我建议您尽可能地进一步操作它(添加时间间隔或更改格式),您可能只需执行以下操作:
printf('%s/%s/%s %s:%s %s', [
$endDate['day'],
$endDate['month'],
$endDate['year'],
$endDate['hour'],
$endDate['min'],
$endDate['meridian'],
]
演示:您可以将您的值组合成一个值日期字符串,然后创建调用
strotime
的DateTime
的新实例
$endtime = [
'month' => '05',
'day' => '30',
'year' => '2017',
'hour' => '10',
'min' => '48',
'meridian' => 'pm'
];
$datetime = DateTime::createFromFormat("Y-m-d h:i A", "{$endtime['year']}-{$endtime['month']}-{$endtime['day']} {$endtime['hour']}:{$endtime['min']} {$endtime['meridian']}");
$time = strtotime("{$endtime['year']}-{$endtime['month']}-{$endtime['day']} {$endtime['hour']}:{$endtime['min']} {$endtime['meridian']}");
没有API函数可以实现这一点。您可以实现自己的方法,其中应如下所示:
/**
* Convert given array to DateTimeObject
* @param $dateArr array containing 'day', 'month', 'year', 'hour', 'min', 'meridian'
* @return DateTime object
*
* 'day' and 'month' must always be 2 numbers
* 'year' must always be 4 numbers
* 'hour' must always be 2 numbers (01-12)
* 'min' must always be 2 numbers (00-59)
* 'meridian' must always be 2 letters ('am' or 'pm')
*/
function createEndDate($dateArr) {
return DateTime::createFromFormat('dmYhia',
$dateArr['day'] .
$dateArr['month'] .
$dateArr['year'] .
$dateArr['hour'] .
$dateArr['min'] .
strtolower($dateArr['meridian']));
}
代码示例:
$yourArr => array(
'month' => '05',
'day' => '30',
'year' => '2017',
'hour' => '10',
'min' => '48',
'meridian' => 'pm'
)
$endDate = createEndDate($yourArr);
// see http://php.net/manual/de/class.datetime.php for docs
echo $endDate->format('u');
我想你看起来像这样吗?即使这样也可以,有没有办法把结果转换成毫秒。结果:
'18/04/2017 04:48 pm'
$yourArr => array(
'month' => '05',
'day' => '30',
'year' => '2017',
'hour' => '10',
'min' => '48',
'meridian' => 'pm'
)
$endDate = createEndDate($yourArr);
// see http://php.net/manual/de/class.datetime.php for docs
echo $endDate->format('u');