Php Symfony 2.6表单验证和错误消息
我对Symfony还很陌生。我已经编写了下面的代码来验证并返回错误消息,如果验证失败。但我只能得到错误消息,而不是验证失败的字段。下面是我的代码:Php Symfony 2.6表单验证和错误消息,php,symfony,symfony-forms,symfony-validator,Php,Symfony,Symfony Forms,Symfony Validator,我对Symfony还很陌生。我已经编写了下面的代码来验证并返回错误消息,如果验证失败。但我只能得到错误消息,而不是验证失败的字段。下面是我的代码: if ($request->isXmlHttpRequest()) { if ($form->isValid()) { //do something here } $errors = $this->get('my_form')->getErrorMes
if ($request->isXmlHttpRequest()) {
if ($form->isValid()) {
//do something here
}
$errors = $this->get('my_form')->getErrorMessages($form);
return new JsonResponse(['errors' => $errors], 400);
}
有人能告诉我,我怎样才能同时获得字段名和错误消息
谢谢为了获取表单的所有错误,请使用
$form->getErrors($deep=true,$flatte=true)
将错误转换为名称作为字段名、键作为消息的数组,如下所示:
$errors = $form->getErrors(true, true);
$errorArray = array();
foreach($errors as $e){
//get the field that caused the error
$field = $e->getOrigin();
$errorArray[$field->getName()] = isset($errorArray[$field->getName()]) ? $errorArray[$field->getName()] : array();
$errorArray[$field->getName()][] = $e->getMessage();
}
下面是我使用的一个函数:
/**
* Get errors from form.
*
* @param \Symfony\Component\Form\FormInterface $form
* @return array
*/
private function getErrorsFromForm(FormInterface $form)
{
$errors = array();
foreach ($form->getErrors() as $error) {
$errors[] = $error->getMessage();
}
foreach ($form->all() as $childForm) {
if ($childForm instanceof FormInterface) {
if ($childErrors = $this->getErrorsFromForm($childForm)) {
$errors[$childForm->getName()] = $childErrors;
}
}
}
return $errors;
}