Php 分包商不在Yii框架内工作

对于我的项目，我需要通过在“Controllers”文件夹中添加分包商来自定义代码。 例如：

在控制器中我添加了

controllers -> customer -> CustomerDetailsController.php

型号：

models -> customer -> Customer.php

views -> customer -> customerdetails -> index.php, admin.php, _form.php .... etc

'urlManager' => array(
                    'urlFormat' => 'path',
                    'showScriptName' => false,
                    'urlSuffix' => '/',
                    //'rules' => $params['url.rules'],
                    //Modified "rules" attribute for hiding index.php and added .htaccess in WebRoot
                    'rules' => array(
                        '<controller:\w+>/<id:\d+>' => '<controller>/view',
                        '<controller:\w+>/<action:\w+>/<id:\d+>' => '<controller>/<action>',
                        '<controller:\w+>/<action:\w+>' => '<controller>/<action>',
                        array('customer/<controller:\w+>/<action:\w+>' => 'customer/<controller>/<action>'),
                    ),
                ),

和视图：

models -> customer -> Customer.php

views -> customer -> customerdetails -> index.php, admin.php, _form.php .... etc

'urlManager' => array(
                    'urlFormat' => 'path',
                    'showScriptName' => false,
                    'urlSuffix' => '/',
                    //'rules' => $params['url.rules'],
                    //Modified "rules" attribute for hiding index.php and added .htaccess in WebRoot
                    'rules' => array(
                        '<controller:\w+>/<id:\d+>' => '<controller>/view',
                        '<controller:\w+>/<action:\w+>/<id:\d+>' => '<controller>/<action>',
                        '<controller:\w+>/<action:\w+>' => '<controller>/<action>',
                        array('customer/<controller:\w+>/<action:\w+>' => 'customer/<controller>/<action>'),
                    ),
                ),

以下是我的

config/main.php

文件：

'import'=>
array(
...
/* Loaded CustomerController model, view and controller */
                'application.controllers.customer.*',
                'application.controllers.models.customer.*',
...
)

及

URL管理器：

models -> customer -> Customer.php

views -> customer -> customerdetails -> index.php, admin.php, _form.php .... etc

'urlManager' => array(
                    'urlFormat' => 'path',
                    'showScriptName' => false,
                    'urlSuffix' => '/',
                    //'rules' => $params['url.rules'],
                    //Modified "rules" attribute for hiding index.php and added .htaccess in WebRoot
                    'rules' => array(
                        '<controller:\w+>/<id:\d+>' => '<controller>/view',
                        '<controller:\w+>/<action:\w+>/<id:\d+>' => '<controller>/<action>',
                        '<controller:\w+>/<action:\w+>' => '<controller>/<action>',
                        array('customer/<controller:\w+>/<action:\w+>' => 'customer/<controller>/<action>'),
                    ),
                ),

当然，我读过有关模块的内容，但我不想为这个功能实现模块，我希望将其作为一个外部实体

那么如何在整个项目中实现这种结构呢？

这是正确的吗

'application.controllers.models.customer.*',

你确定那是你的类文件的路径吗？可能是这样的：

application.models.Customer

---

对吧?？我认为类名需要大写才能在别名中使用。（文件本身可能是Customer.php，而不是Customer.php）。

最后一个url重写规则不应包装在数组中，即

'customer/<controller:\w+>/<action:\w+>' => 'customer/<controller>/<action>',

“客户//”=>“客户//”，

而不是

array('customer/<controller:\w+>/<action:\w+>' => 'customer/<controller>/<action>'),

array（'customer/'=>'customer/'），

---

此外，您还应确保主控制器文件夹中没有

CustomerController

C'mon模块很酷：）这个错误看起来好像找不到其他类，而不是那个控制器。你试过空动作吗

CustomerDetails

虽然它应该报告

CustomerDetailsController

但您是否尝试了不带“customer”的url，即

../index.php/CustomerDetails/

？如果是，它能起作用吗？@topher:是的，我试过了，但不起作用