Php MySQL：如何将结果限制在最后5行

这显示了最近10个新结果，所有结果都正常

$query = "SELECT s.name AS song,
                 SUM(v.hit_shit) AS hit,
                 COUNT(v.hit_shit) - SUM(v.hit_shit) AS shit,
                 MAX(date_voted) AS last_vote
            FROM songs AS s
           INNER JOIN votes AS v ON v.song_id = s.id
           WHERE v.date_voted >= CURDATE()
           GROUP BY s.id
           ORDER BY last_vote DESC
           LIMIT 10";
$song = mysql_query($query);

但这场演出全部结束，但我只需要5个：(

$query=“选择s.name作为歌曲，
求和（v.hit_shit）为hit，
计数（v.hit_-shit）-将（v.hit_-shit）总和为shit
从歌曲到音乐
内部连接投票作为v ON v.song_id=s.id上的v
其中v.date_投票>=CURDATE（）
和v.date_投票

---

p、 抱歉4我的坏英语

在您的查询末尾添加限制5

$query = "SELECT s.name AS song,
                 SUM(v.hit_shit) AS hit,
                 COUNT(v.hit_shit) - SUM(v.hit_shit) AS shit,
                 MAX(date_voted) AS last_vote
            FROM songs AS s
           INNER JOIN votes AS v ON v.song_id = s.id
           WHERE v.date_voted >= CURDATE()
           GROUP BY s.id
           ORDER BY last_vote DESC
           LIMIT 5";

$song = mysql_query($query);

$query = "SELECT s.name AS song,
                 SUM(v.hit_shit) AS hit,
                 COUNT(v.hit_shit) - SUM(v.hit_shit) AS shit
            FROM songs AS s
           INNER JOIN votes AS v ON v.song_id = s.id
           WHERE v.date_voted >= CURDATE()
             AND v.date_voted < CURDATE() + INTERVAL 1 DAY
           GROUP BY s.id
           ORDER BY hit DESC, shit ASC, song ASC
           LIMIT 5";

$song = mysql_query($query);

您应该在查询末尾添加参数“LIMIT”

$query = "SELECT s.name AS song,
                 SUM(v.hit_shit) AS hit,
                 COUNT(v.hit_shit) - SUM(v.hit_shit) AS shit,
                 MAX(date_voted) AS last_vote
            FROM songs AS s
           INNER JOIN votes AS v ON v.song_id = s.id
           WHERE v.date_voted >= CURDATE()
           GROUP BY s.id
           ORDER BY last_vote DESC
           LIMIT 5";

$song = mysql_query($query);

$query = "SELECT s.name AS song,
                 SUM(v.hit_shit) AS hit,
                 COUNT(v.hit_shit) - SUM(v.hit_shit) AS shit
            FROM songs AS s
           INNER JOIN votes AS v ON v.song_id = s.id
           WHERE v.date_voted >= CURDATE()
             AND v.date_voted < CURDATE() + INTERVAL 1 DAY
           GROUP BY s.id
           ORDER BY hit DESC, shit ASC, song ASC
           LIMIT 5";

$song = mysql_query($query);

$query=“选择s.name作为歌曲，
求和（v.hit_shit）为hit，
计数（v.hit_-shit）-将（v.hit_-shit）总和为shit
从歌曲到音乐
内部连接投票作为v ON v.song_id=s.id上的v
其中v.date_投票>=CURDATE（）
和v.date_投票

---

编辑：修改代码格式。

将限制10更改为限制5您在查询中没有注意到限制10吗？我会尝试的第一件事是将其从10更改为5。为什么会有这么多狗屎？关于第一个代码，我知道，但第二个（这就是限制返回查询数量的方法。如果您只想要5个结果，请限制前5个结果。哇，谢谢，真的很大谢谢：）如果答案对您有效，您应该接受它。@user2912266表格中的歌曲和投票是否很大？阅读100000条或更多记录？