Php 我编写了一些从数据库中获取数据的代码,在mysql中代码正常,在pdo中则不正常 这是mysql连接编码,工作正常
与我使用pdo连接编写的代码相同,它不起作用。我是php新手,请帮助我解决此问题。 提前谢谢Php 我编写了一些从数据库中获取数据的代码,在mysql中代码正常,在pdo中则不正常 这是mysql连接编码,工作正常,php,mysql,pdo,Php,Mysql,Pdo,与我使用pdo连接编写的代码相同,它不起作用。我是php新手,请帮助我解决此问题。 提前谢谢 <?php error_reporting(0); ini_set('max_execution_time', 600); require_once 'config.php'; if(isset($_GET["nm_mask"])) $nm_mask = $_GET['nm_mask']; else $nm_mask = ""; if(isset($_GET
<?php
error_reporting(0);
ini_set('max_execution_time', 600);
require_once 'config.php';
if(isset($_GET["nm_mask"]))
$nm_mask = $_GET['nm_mask'];
else
$nm_mask = "";
if(isset($_GET["cd_mask"]))
$cd_mask = $_GET['cd_mask'];
else
$cd_mask = "";
if(isset($_GET["func"]))
$func = $_GET['func'];
else
$func = "";
$where = "WHERE 1=1";
if($nm_mask!='')
$where.= " AND Login LIKE '$nm_mask%'";
if($cd_mask!='')
$where.= " AND Manager_Login LIKE '$cd_mask%'";
if($func!='')
$where.= " AND Function LIKE '$func%'";
$page = $_GET['page']; // get the requested page
$limit = $_GET['rows']; // get how many rows we want to have into the grid
$sidx = $_GET['sidx']; // get index row - i.e. user click to sort
$sord = $_GET['sord']; // get the direction
if(!$sidx) $sidx =1; // connect to the database
$result = mysqli_query("SELECT COUNT(*) AS count FROM EmpMasterTB ".$where);
$row = mysqli_fetch_array($result,MYSQLI_ASSOC);
$count = $row['count'];
if( $count >0 ) {
$total_pages = ceil($count/$limit);
} else {
$total_pages = 0;
}
if ($page > $total_pages) $page=$total_pages;
if ($limit<0) $limit = 0;
$start = $limit*$page - $limit; // do not put $limit*($page - 1)
if ($start<0) $start = 0;
$SQL = "SELECT * from EmpMasterTB ". $where ." ORDER BY $sidx $sord LIMIT $start , $limit";
$result = mysqli_query( $SQL ) or die("Couldn?t execute query.".mysqli_error());
$responce->page = $page;
$responce->total = $total_pages;
$responce->records = $count;
$i=0;
while($row = mysqli_fetch_array($result,MYSQLI_ASSOC)) {
$responce->rows[$i]['id']=$row[WeekNo].$row[Login];
$responce->rows[$i]['cell']=array($row['WeekNo'],$row['WeekBeginning'],$row['SITE'],$row['Name'],$row['WFH'],$row['Login'],$row['Manager_Login'],$row['Lead'],$row['Cost_center'],$row['Business_Title'],$row['Function'],$row['Workgroup'],$row['Login_time'],$row['ROLE'],$row['Secondary_Skill'],$row['Weekoff'],""); $i++;
}
echo json_encode($responce);
?>
您错过了for循环,并且没有在json_encode()中传递响应。
请检查我的以下代码:
/*** echo number of columns ***/
$objs = $stmt->fetch(PDO::FETCH_OBJ);
/*** loop over the object directly ***/
foreach($objs as $obj)
{
$responce->rows[$i]['id']=$obj->WeekNo.$obj->Login;
$responce->rows[$i]['cell']=array($obj->WeekNo ,$obj->WeekBeginning ,$obj->SITE ,$obj->Name ,$obj->WFH ,$obj->Login ,$obj->Manager_Login ,$obj->Lead ,$obj->Cost_center ,$obj->Business_Title ,$obj->Function ,$obj->Workgroup ,$obj->Login_time ,$obj->ROLE ,$obj->Secondary_Skill ,$obj->Weekoff ); $i++;
}
echo json_encode($responce );
“不工作”,什么不工作?请启用错误报告并发布发生的消息错误报告(0)代码>这违背了调试的目的。应该启用它。我认为$dbh->exec
应该是$dbh->execute
它没有从数据库中获取数据,也没有生成错误日志。。
/*** echo number of columns ***/
$objs = $stmt->fetch(PDO::FETCH_OBJ);
/*** loop over the object directly ***/
foreach($objs as $obj)
{
$responce->rows[$i]['id']=$obj->WeekNo.$obj->Login;
$responce->rows[$i]['cell']=array($obj->WeekNo ,$obj->WeekBeginning ,$obj->SITE ,$obj->Name ,$obj->WFH ,$obj->Login ,$obj->Manager_Login ,$obj->Lead ,$obj->Cost_center ,$obj->Business_Title ,$obj->Function ,$obj->Workgroup ,$obj->Login_time ,$obj->ROLE ,$obj->Secondary_Skill ,$obj->Weekoff ); $i++;
}
echo json_encode($responce );